Answer:
V1 = 60 km/h
V2 = 40 Km/h
Step-by-step explanation:
The speed of an object is defined as
Speed = distance / time
Let
V1 be the speed of the faster car
V2 be the speed of the other car
t1 the time it took for the first car to arrive
t2 the time it took for the second car to arrive
d1 the distance traveled by first car
d2 the distance traveled by second car
We know thanks to the problem that
V1 = V2 + 20 Km/h
t1 = t2 - 1 hour
d1 = d2 = 120 Km
d1 = V1 * t1
d2 = V2* t2
V1 * t1 = V2* t2
V1* t1 = (V1 -20)*(t1 +1)
The system of equations
(V1 -20)*(t1 +1) = 120
V1 * t1 = 120
120 + (120/t1) -20*t1 = 140
(120/t1) -20*t1 = 20
Which gives,
t1 = 2
This means
V1 = 60 km/h
V2 = V1 - 20 Km/h = 40 Km/h
Answer:
-48/15, simplified to -16/5
Step-by-step explanation:
The reciprocal of -3/8 is -8/3. So the equation will be 6/5 x -8/3. Multiply numerators then multiply denominators to get -48/15. This can simplify to -16/5 by dividing both by 3.
It’s 7 in that’s the only answer that makes sense
Answer:
stdgjdfsfdmgdlgyhkagrhnalghgkfkikah sJo
Answer:
It is undefined
Step-by-step explanation:
