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fomenos
4 years ago
5

What is the least common multiple of 2,6 and 8a.24b.48c.12d.2

Mathematics
2 answers:
allochka39001 [22]4 years ago
6 0
D because 2 can go into 2  1 time 6 can go into 2 3 times and also 8 can go into 2 4 times
Furkat [3]4 years ago
5 0
C. 12 id your answer
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Which statements describe a parallelogram that must be a rhombus?
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Answer:

3 and 5.

Step-by-step explanation:

A parallelogram which is a rhombus has perpendicular diagonals.

Also a parallelogram which is a rhombus has a pair of congruent consecutive sides.

6 0
3 years ago
Y+100=x^2 graph the following equation
enot [183]
Slope-intercept form is the easiest to help visualize graphs so you would isolate the y making it y = x^2 - 100. It is now clear to see that this is the parent graph of y=x^2 shifted down 100 units.
8 0
4 years ago
Let f(x) = 5x ^ 2 - x + 1 and g(x) = - 3x . Evaluate the composition (fg)(1)
nlexa [21]
F(x) = 5(-3x) ^2 - (-3x) + 1
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5 0
3 years ago
Read 2 more answers
1. Let L be a list of numbers in non-decreasing order, and x be a given number. Describe an algorithm that counts the number of
e-lub [12.9K]

Answer:

Algorithm

Start

Int n // To represent the number of array

Input n

Int countsearch = 0

float search

Float [] numbers // To represent an array of non decreasing number

// Input array elements but first Initialise a counter element

Int count = 0, digit

Do

// Check if element to be inserted is the first element

If(count == 0) Then

Input numbers[count]

Else

lbl: Input digit

If(digit > numbers[count-1]) then

numbers[count] = digit

Else

Output "Number must be greater than the previous number"

Goto lbl

Endif

Endif

count = count + 1

While(count<n)

count = 0

// Input element to count

input search

// Begin searching and counting

Do

if(numbers [count] == search)

countsearch = countsearch+1;

End if

While (count < n)

Output count

Program to illustrate the above

// Written in C++

// Comments are used for explanatory purpose

#include<iostream>

using namespace std;

int main()

{

// Variable declaration

float [] numbers;

int n, count;

float num, searchdigit;

cout<<"Number of array elements: ";

cin>> n;

// Enter array element

for(int I = 0; I<n;I++)

{

if(I == 0)

{

cin>>numbers [0]

}

else

{

lbl: cin>>num;

if(num >= numbers [I])

{

numbers [I] = num;

}

else

{

goto lbl;

}

}

// Search for a particular number

int search;

cin>>searchdigit;

for(int I = 0; I<n; I++)

{

if(numbers[I] == searchdigit

search++

}

}

// Print result

cout<<search;

return 0;

}

8 0
3 years ago
What is the x please answer me quick ​
nordsb [41]
First u do a squared +b squared =c squared aka pythagorean theorem then so u already have c squared so you would do 5x5=25 and 13x13=169 so then the equation would be 25+?=169 then do 169-25 which equals 144 and then do the square root of that which is 12 THE ANSWER IS 12
4 0
3 years ago
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