Question

2x+3y=4

Answer 1

Answer:

Option D.

Step-by-step explanation:

we have

$2x+3y=4$ -----> equation A

$2x-5y=-12$  -----> equation B

Solve the system by elimination

Multiply both sides equation A by -1

$-1(2x+3y)=-1(4)$

$-2x-3y=-4$-----> equation C

Adds equation C and equation B

$-2x-3y=-4\\2x-5y=-12\\------\\-3y-5y=-4-12\\-8y=-16\\y=2$

Find the value of x

substitute the value of y in either equation

$2x+3(2)=4\\2x+6=4\\2x=-2\\x=-1$

The solution is the point (-1,2)

In this problem Option A,B and C are correct

The option D not result in a system with a pair of opposite terms

because

Multiply both sides of equation B by -3

$-3(2x-5y)=-3(-12)$

$-6x+15y=36$  -----> equation C

Multiply both sides of equation A by 5$5(2x+3y)=5(4)$

$10x+15y=20$  ----> equation D

so

equation C and equation D not have a pair of opposite terms