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gavmur [86]
3 years ago
11

P = a + (n - 1)b, for b

Mathematics
2 answers:
exis [7]3 years ago
8 0
P = a + (n - 1)b   Subtratc a from both sides
P - a = (n - 1)b   Divide both sides by (n - 1)
\frac{P - a}{n - 1} = b   Switch the sides to make it easier to read
b = <span>\frac{P - a}{n - 1}</span>
sweet [91]3 years ago
5 0
The answer is b=P-a-(n+1) all you had to do was the a and the parenthesis from the b and put it on the other side
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Answer:

answer will be an=3n+11

Step-by-step explanation:

because when we substitute them...it make sense.

<em>the</em><em> </em><em>rule</em><em> </em><em>is</em><em> </em><em>an</em><em>=</em><em>3</em><em>n</em><em>+</em><em>1</em><em>1</em>

<em>lets</em><em> </em><em>substitute</em><em>:</em>

<em>(</em><em>i</em><em>)</em><em>.</em><em>1</em><em>4</em><em>=</em><em>3</em><em>(</em><em>1</em><em>)</em><em>+</em><em>1</em><em>1</em>

<em>(</em><em>ii</em><em>)</em><em>1</em><em>7</em><em>=</em><em>3</em><em>(</em><em>2</em><em>)</em><em>+</em><em>1</em><em>1</em>

<em>(</em><em>iii</em><em>)</em><em>2</em><em>0</em><em>=</em><em>3</em><em>(</em><em>3</em><em>)</em><em>+</em><em>1</em><em>1</em>

<em>(</em><em>iv</em><em>)</em><em>2</em><em>3</em><em>=</em><em>3</em><em>(</em><em>4</em><em>)</em><em>+</em><em>1</em><em>1</em>

<em>it</em><em> </em><em>does</em><em> </em><em>make</em><em> </em><em>sense</em><em>.</em><em>.</em><em>.</em><em>.</em>

<em>I hope it will help u</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0
2 years ago
If you input 2 and 2 is the output and if you input 4 and the output is 6 and if you input 5 and the output is 8 what is the inp
Dominik [7]

Answer:

11

Step-by-step explanation:

3 0
3 years ago
Molly bought two cabbages for 1.80 how many cabbages could she buy with 28.80
Alika [10]
She can buy 16 cabbages .
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3 years ago
Given: <br><br>EM, EQ-secants<br><br>Prove: MP·EW=WQ·EP
Dennis_Churaev [7]

Answer:

Step-by-step explanation:

A secant is a straight line from a point outside a given circle that passes through two points on its circumference.

From the given diagram, EM and EQ are secants.

Thus,

<PEW ≅ <WEP    (common angles)

<EMP ≅ <EQW (secant-chord theorem)

<WMP ≅ <PQM (inscribed angles of arc WP)

Therefore,

\frac{EW}{WM} = \frac{EP}{PQ}   (corresponding sides of a triangle)

This implies that,

EW*PQ = EP*WM

Therefore,

MP*EW = WQ*EP  (properties of a similar triangle)

7 0
2 years ago
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777dan777 [17]

Answer:

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Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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