Question

Rearranging literal equations for z

Answer 1

Answer:

$z = \frac{3n - 3}{6 - 2n}$

Step-by-step explanation:

$\frac{1}{(n-1)^{\frac{1}{3} } } = (\frac{2z + 3}{4z} )^{\frac{1}{3} }$

cubing on both sides we get

$\frac{1}{n-1} = \frac{2z + 3}{4z}$

4z = (2z+3)(n-1)

4z = 2nz + 3n - 2z - 3

4z - 2nz + 2z = 3n - 3

z(6 - 2n) = 3n - 3

$z = \frac{3n - 3}{6 - 2n}$