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Y_Kistochka [10]
3 years ago
5

Suppose that 1% of the students in a school have head lice and the test for head lice is accurate 75% of the time. What is the p

robability that a student in the school has head lice, given that the test came back positive?,
Mathematics
2 answers:
Pavlova-9 [17]3 years ago
4 0
Answer: There is a 2.9% chance that a person has head lice given that the test is positive. (I know that sounds very low, but watch the math)

Imagine there are 10,000 students in the school. If 1% have lice, that makes 100 students that have it and 9,900 that don't.

Assume the test was given to all students. Out of the 100 that have lice, only 75 would get a positive test because it is only 75% accurate.

Now, out of the 9,900 student who don't have lice, 25% of them would get a positive test, because the test is only 75% accurate. That is 2,475 false positive tests!!!

So we had a total of 2,550 positive tests, but only 75 of those students actually have lice. 75 out of 2550 is 2.9%.


Stells [14]3 years ago
3 0

Answer:

2.9% (APEX)

Step-by-step explanation:

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We can start using the definition of displacement in one dimension between any 2 points which is the difference between them, so we have

\Delta s = s_2-s_1

And apply it to get the horizontal and vertical displacements.

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Linear displacements.

Using the definition of displacement, we can write the horizontal displacement as

\Delta x = x_2-x_1

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In the same manner we can look at the y components of those points to find the vertical displacement

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Thus the horizontal displacement is 11 units and the vertical displacement is 9 units.

Projection angle.

The projection angle with respect the horizontal is the angle that is made between the line that connects the points P1 and P2 and the horizontal, so we can use the linear displacements previously found to write

\tan(\theta) = \cfrac{\Delta y}{\Delta x}

Solving for the angle we get

\theta = \tan^{-1}\left(\cfrac{\Delta y}{\Delta x}\right)

Replacing values

\theta = \tan^{-1}\left(\cfrac{9}{11}\right)

Which give us

\theta = 39.3^\circ

So the projection angle is 39.3 degrees.

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