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Vesnalui [34]
3 years ago
15

30 Points Use Scientific Notation Put Greater Than Less Than Or Equal To In Each Box!

Mathematics
1 answer:
riadik2000 [5.3K]3 years ago
3 0

Answer:

5. >

6. >

7. <

8. <

9. =

10. >

11. >

12. >

Step-by-step explanation:

5. 9.33 x 10³ = 9330

9330 > 933

6. 2.88 x 10⁻⁵ = 0.0000288

2.9 x 10⁻⁶ = 0.0000029

0.0000288 > 0.0000029

7. 0.33 x 10⁻⁷ = 0.000000033

3.7 x 10⁻⁶ = 0.0000037

0.000000033 < 0.0000037

8. 4.9 x 10⁴ = 49000

4.79 x 10⁵ = 479000

49000 < 479000

9. 3.0 x 10⁶ = 3000000

30 x 10⁵ = 3000000

3000000 = 3000000

10. 2.2 x 10⁻³ = 0.0022

1.7 x 10⁻³ = 0.0017

0.0022 > 0.0017

11. 2.1 x 10⁷ = 21000000

2 million = 2000000

21000000 > 2000000

12. 5.2 x 10¹¹ = 520000000000

8.7 x 10¹⁰ = 87000000000

520000000000 > 87000000000

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OAA', OBB', and OCC' are straight lines. Triangle ABC is mapped onto Triangle A'B'C' by an enlargement with center O. What is th
bazaltina [42]

Answer:

(D) 2

Step-by-step explanation:

The scale factor of the enlargement of ΔABC to ΔA'B'C' is given by the ratio of the length of the corresponding sides of ΔA'B'C' and ΔABC

Therefore, we have;

The \ scale \ factor = \dfrac{Length \ of \overline  {B'C'}}{Length \ of \overline {BC}} =  \dfrac{Length \ of \overline  {A'C'}}{Length \ of \overline {AC}} =  \dfrac{Length \ of \overline  {A'B'}}{Length \ of \overline {AB}}

\dfrac{Length \ of \overline  {B'C'}}{Length \ of \overline {BC}} =  \dfrac{2 \ units}{1 \ unit} = 2

\dfrac{Length \ of \overline  {A'C'}}{Length \ of \overline {AC}} =  \dfrac{4 \ units}{2 \ units} = 2

\dfrac{Length \ of \overline  {A'B'}}{Length \ of \overline {AB}} =  \dfrac{2 \cdot \sqrt{5}  \ units}{\sqrt{5}  \ units} = 2

Therefore, the scale factor = 2

6 0
3 years ago
How do you solve this equation: 80x =
Pepsi [2]

Answer:

Divide by 80 on both sides

7 0
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Calculate the slope of the line that goes through the points (2, 0) and (−4, 6)
Ivenika [448]

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-4 + (-1) on a number line
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-5

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+-=-

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5 0
3 years ago
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3. Given: Circle Q<br>&lt;A = 35<br>Find: m AB​
Agata [3.3K]

Answer:  110°

<u>Step-by-step explanation:</u>

∠A ≅ ∠B  

since ∠A = 35° (given), then ∠B = 35°

Use the Triangle Sum Theorem to find ∠C:

∠A + ∠B + ∠Q = 180°

35° + 35° + ∠Q = 180°

     70°    + ∠Q = 180°

                 ∠Q = 110°

The central angle (∠AQB) ≅ arc AB

since ∠AQB = 110° (solved above), then arc AB = 110°

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3 years ago
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