Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Answer:
1. 13+10i
2. 28-(-4i)
3. -14-1i
4. 4 -i
5. 15+ 10i
6.8 - 5i^2
Step-by-step explanation:
He initial value is 32,000 and the value after 13 yrs is 8133.97
Answer:
87 feet
Step-by-step explanation:
8 feet below sea level would be -8
95 feet above sea level would be +95
so it would be -8+95
-8+95=87
:)
