Answer:
Fe is limiting reactant and 3.00g of Fe2O3 will be produced
Explanation:
To solve this question we must convert the mass of each reactant to moles and, using the reaction we can find limiting reactant. With moles of limiting reactant we can find moles of Fe2O3 and its mass as follows:
<em>Moles Fe -Molar mass: 55.845g/mol-</em>
2.1g * (1mol / 55.845g) = 0.0376 moles
<em>Moles O2 -Molar mass: 32g/mol-</em>
2.1g * (1mol / 32g) = 0.0656 moles
For a complete reaction of 0.0656 moles of O2 are needed:
0.0656moles O2 * (4mol Fe / 3 mol O2) = 0.0875 moles Fe
As there are just 0.0376 moles,
Fe is limiting reactant
The mass of Fe2O3 is:
<em>Moles:</em>
0.0376 moles Fe* (2mol Fe2O3 / 4mol Fe) = 0.0188 moles Fe2O3
<em>Mass:</em>
0.0188 moles Fe2O3 * (159.69g / mol) =
3.00g of Fe2O3 will be produced
Answer:
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Answer:
1
Explanation:
I would say 1 because that configuration has 7 valence electrons. The goal of the atom is to gain a full octet so it just needs to gain 1 more electron to get the full octet. To get the one electron to fill the valence shell it would only need to have 1 covalent bond.
I hope this helps. Let me know if anything is unclear.
For the first one I think it’s A, and I think the second one is C. Those seem most logical.
Answer:
The pressure law states that for a constant volume of gas in a sealed container the temperature of the gas is directly proportional to its pressure. ... This means that they have more collisions with each other and the sides of the container and hence the pressure is increased.
