13.5 I think tell me if it works
H(x) = (x - 5)²
h(x) = (x - 5)(x - 5)
h(x) = x(x - 5) - 5(x - 5)
h(x) = x(x) - x(5) - 5(x) + 5(5)
h(x) = x² - 5x - 5x + 25
h(x) = x² - 10x + 25
Answer:
the firsst one trust bruv
Step-by-step explanation:
Answer:
The feasible region is unbounded which is the shaded portion in the graph.
Step-by-step explanation:
Given that, the number of hours Jessie works as a teacher and tutor is y and x respectively, which can't be negative.
So,
y\ge0\;\cdots(ii)
She works at least 36 hours a week.
She works as a teacher for al least twice the number of hours she works as a tutor.
The boundary of the inequalities from equations (i), (ii), (iii), and (iv) are
and .
The feasible region is the shaded portion which is the unbounded region as shown in the graph. Any point P(x,y) from the feasible region will satisfies all the constraints.
Answer:
Margin of Error = 0.5
Step-by-step explanation:
Using this formula Z (s/√n)
Where
S = 1.8----------------------------- Standard Deviation
n = 36 ----------------------------------Number of observation
Z = 1.645 ------------------------------The chosen Z-value from the confidence table below
Confidence Interval || Z
80%. || 1.282
85% || 1.440
90%. || 1.645
95%. || 1.960
99%. || 2.576
99.5% || 2.807
99.9%. || 3.291
Substituting these values in the formula
Margin of Error = 1.645 * (1.8/√36)
Margin of Error = 1.645 * (1.8/6)
Margin of Error = 1.645 * 0.3
Margin of Error = 0.4935
Margin of Error = 0.5 (Approximated)