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3 years ago

Find the exact length of the third side. 6 9

Mathematics

2 answers:

egoroff_w [7]3 years ago

5 0

Step by step:
right triangle so use pythagorean theorem
formula is a^2+b^2=c^2
9 is c cause its hypotenuse
so 6^2+b^2=9^2
36+b^2=81
-36 -36
________
b^2=45
b is the sqrt of 45 so about 6.71 so ur right

solniwko [45]3 years ago

3 0

Answer:

The square root of 45

Step-by-step explanation:

9^2-6^2=c^2

81-36=c^2

45=c^2

c=sqrt(45)

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LUCKY_DIMON [66]

Answer:

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3 years ago

Is 41/50 closer to 9/11 or 10/11? Verify your answer

Setler79 [48]

Which one is closer to 41/50, 9/11 or 10/11
=> Let’s find the value of the two given choices to be able to fin which one is closer to 41/50
=> 9/11 convert this to decimal number
=> 9 divide by 11
=> 0.82

=> 10/11 convert in decimals
=> 10 divide by 11
=> 0.91

Now, we have the value of both numbers, let’s find the value of 41/50
=> 41/50
=> 41 divided by 50
=> 0.82

Thus, the closer number to 41/50 is the 9/11 because they both have 0.82 decimal value.

7 0

3 years ago

Find the length of AB

aniked [119]

FIRST QUESTION
Given points are:
A(2, -4) and B(6, 2)
Now, Use the distance formula.
distance formula = $\sqrt{ (x_{2}- x_{1})^{2} + ( y_{2} - y_{1} )^{2} }$

Now, plug the values into the formula, So,
distance = $\sqrt{ (6- 2)^{2} + ( 2 - (-4))^{2} }$

= $\sqrt{ (6- 2)^{2} + ( 2 +4))^{2} }$

= $\sqrt{ (4)^{2} + ( 6))^{2} }$

= $\sqrt{ 16+36}$

= $\sqrt{52}$

= $2 \sqrt{13}$

So, the length of AB is $2 \sqrt{13}$ .

THIRD QUESTION
Two points given are:
A(3, -2) and B(1, 1)
Also given that B is the midpoint of AC.

Let, the co-ordinates of C be C(a, b).
Now, using midpoint formula,
Midpoint = $(\frac{ x_{1}+ x_{2} }{2} , \frac{ y_{1}+ y_{2} }{2} )$

$(1, 1)=(\frac{ 3+ a }{2} , \frac{ -2+b }{2} )$

Now, equaling the ordered pair, we have,

$1=\frac{ 3+ a }{2}$ .............equation (1)

$1=\frac{ -2+b }{2}$ ................equation (2)

Now, taking equation (1)
$1=\frac{ 3+ a }{2}$

$1*2=3+a$

$2-3=a$

$a=-1$

Now, taking equation (2)
$1=\frac{ -2+b }{2}$

$1*2=-2+b$

$2+2=b$

$b=4$

So, the co ordinates of C are (a, b) which is (-1 , 4)


SECOND QUESTION:
Given equations are:
2x + 3y = 14.....................equation (1)
-4x + 2y = 4 .....................equation (2)
Taking equation (2)
-4x + 2y = 4
2y = 4 + 4x
y = (4 + 4x) / 2
y = 2 + 2x .......................equation (3)
Now, Taking equation (1)
2x + 3y = 14
Substituting the value of y from equation (3), we get,
2x + 3(2 + 2x) = 14
2x + 6 + 6x = 14
8x = 14 - 6
x = (14 - 6) / 8
x = 1

Taking equation (3)
y = 2 + 2x
Now, substituting the value of x in equation (3), we get,
y= 2 + 2 (1)
y = 2 + 2
y = 4

So, x=1 and y=4

6 0

3 years ago

If f(x)=4x+3 and g(x)=x^2-3 then f(g(2))

grandymaker [24]

Answer:

f(g(2))=7

Step-by-step explanation:

The Composite Function

Given f(x) and g(x) as real functions, the composite function $(f\circ g)(x)$ is defined as: