The probability of selection 2 black cups one after another one without replacement is 1/91
<h3>What is the probability of selection 2 black cups one after another one without replacement?</h3>
The given parameters are:
Green = 4
Blue = 8
Black = 2
Given that the selection is without replacement, this means that the number of cups reduces when one is selected
So, we have:
P(2 Black cups) = P(Black) * P(Black)
This gives
P(2 Black cups) = 2/(4 + 8 + 2) * (2 - 1)/(4 + 8 + 2 - 1)
Evaluate
P(2 Black cups) = 2/14 * 1/13
This gives
P(2 Black cups) = 1/91
Hence, the probability of selection 2 black cups one after another one without replacement is 1/91
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Answer: A = 216; B = 35
Step-by-step explanation:
Based on the information given in the question, we can then make it into a mathematical equation. This will be:
A + B = 251 ....... i
A - B = 181 ....... ii
From equation i,
A = 251 - B
Put the value of A into equation ii
A - B = 181
(251 - B) - B = 181
251 - B - B = 181
251 - 2B = 181
2B = 251 - 181
2B = 70
B = 70/2
B = 35
Since A = 251 - B
A = 251 - 35
A = 216
Answer:
Step-by-step explanation:
Hello, please consider the following.
Hope this helps.
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Answer:
It''s d
Step-by-step explanation:
If he had 150 to spend on 3 pairs of pants and 30 left over the equation would be 3x+30=150. In case you need to know how much a pair is it would be $40