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2 years ago

What is 5 more than the quotient of a number and 6 equals 7

Mathematics

1 answer:

loris [4]2 years ago

6 0

Answer:

x/6 + 5 = 7

x/6 = 2

x = 12

Step-by-step explanation:

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Solve the inequality 5x - 4 > 4 - 3x<br>

olga55 [171]

Answer:

x>1

Step-by-step explanation:

5x - 4 > 4 - 3x

Add 3x to each side

5x+3x - 4 > 4 - 3x+3x

8x -4 > 4

Add 4 to each sdie

8x-4+4 > 4+4

8x> 8

Divide each side by 8

8x/8 >8/8

x > 1

3 0

3 years ago

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The fraction 12/20 express in its simplest form is:

goldfiish [28.3K]

Divided both of the numbers by 4, and you get the fraction of 3/5

8 0

3 years ago

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If the diameter of an entire coconut is 5 inches, and the coconut meat is 1 inch thick.

Arturiano [62]

Answer:

V=33.51in^3

Step-by-step explanation:

5inch-1 in

=4inch

divide by 2 because the problem gives diameter, not radius. (radius is half of diameter)

The space inside is a sphere so it will be

V=4/3πr^3

V=4/3*pi*(2)^3

V=33.51 inch cubed

6 0

3 years ago

How do find the height of the parallelogram?

Yanka [14]

You need to multiply the base by the height.

5 0

3 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

2 years ago