Answer: The distace between midpoints of AP and QB is 
.
Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:
AP + PQ + QB = a
According to the question, AP = 2 PQ = 2QB, so:
PQ = 
QB =
Substituing:
AP + 2*() = a
2AP = a
AP = 
Since the distance is between midpoints of AP and QB:
2QB = AP
QB =
QB = 
QB = 
MIdpoint is the point that divides the segment in half, so:
<u>Midpoint of AP</u>:
<u>Midpoint of QB</u>:
The distance is:
d = 
d =
Answer:
25.5 and 37.5
Step-by-step explanation:
x+y=63
x-y = 12 then x = 12 + y sub this into the first equation
(12+y) + y = 63
12 + 2y = 63
2y = 51
y = 25.5 then x = 37.5
200 - (2x) = 42
200 - 42 = 2x
158/2 = 2x/2
x = 79
he is 79 years old
hope this helps
a wise 'old' man
Answer:
you must send 25 msgs to have the same cost
Step-by-step explanation:
x = n of messages
15+ (0.25x ) = 20 + (0.05x)
0.2x = 5
x = 25
The volume we're looking for is the volume of both cones in the figure.
The volume of a cone is 
.
So, 
.
<u>Cone 1's variables:</u>
r = 2.6
h = 5
<u>Cone 2's variables:</u>
r = 2.6
h = 3
Now we can just plug and chug!
![V_{tot} = [(3.14)(2.6^2)(\frac{5}{3} )] + [(3.14)(2.6^2)\frac{3}{3} )]\\V_{tot} = [(3.14)(6.76)(1.67)] + [(3.14)(6.76)(1)]\\V_{tot} = (35.45) + (21.23)\\V_{tot} = 56.68](https://tex.z-dn.net/?f=V_%7Btot%7D%20%3D%20%5B%283.14%29%282.6%5E2%29%28%5Cfrac%7B5%7D%7B3%7D%20%29%5D%20%2B%20%5B%283.14%29%282.6%5E2%29%5Cfrac%7B3%7D%7B3%7D%20%29%5D%5C%5CV_%7Btot%7D%20%3D%20%5B%283.14%29%286.76%29%281.67%29%5D%20%2B%20%5B%283.14%29%286.76%29%281%29%5D%5C%5CV_%7Btot%7D%20%3D%20%2835.45%29%20%2B%20%2821.23%29%5C%5CV_%7Btot%7D%20%3D%2056.68)
V = c. 56.6 cubic units
