1.) The interval of the value of x is from -5 to 1, inclusive. Remember that what is asked is the absolute value, thus the sign does not matter even if you have to subtract x from 5. Thus, the maximum value would be obtained if the x is smaller, which is 1. The minimum value is obtained when x=-5.
Absolute maximum value:
x = - 5f(-5) = ║5 - 7(-5)^2║ = ║-170║=
170Absolute minimum value:
x = 1f(1) = ║5 - 7(1)^2║ = ║-2║=
2
2.) The Mean Value Theorem (MVT) applies to functions that are continuous and differentiable on the closed and open interval of a to b, respectively. Since the function is a quadratic function, MVT can be applied. Then, this means that there is a value of c which is between a and b. This could be determined using this formula according to MVT:

The differentiated form would be f'(x) = -2x. Then,


Thus, x = -1, x = -1/2, and x=0 all lie in the function 4-x^2.
9514 1404 393
Answer:
72°
Step-by-step explanation:
The external angle E is half the difference of subtended arcs CG and DF.
E = (CG -DF)/2
2E = CG -DF . . . . . . multiply by 2
DF = CG -2E = 160° -2(44°) . . . . . add DF-2E to both sides; substitute values
arc DF = 72°
The answer is 75° because all three angles of a triangle must add to 180°
Answer:
The value of b would be $25 since it's the initial amt. The value of m would be $8. The equation would be y=8x+25