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3 years ago

I need help with this please

Mathematics

1 answer:

Harlamova29_29 [7]3 years ago

3 0

-12y+14-9y=14
-21y=0
y=0, x=7

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tankabanditka [31]

Answer:

16/13

Step-by-step explanation:

the error is when it was divided, one of the fractions should be reversed to be multiplied

4 ÷ 13

7. 28

4 × 28 ,like this

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= 112 ,divide both by 7

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3 years ago

63+d=105 What is this answerrr

Allushta [10]

Answer:

Step-by-step explanation:

105 - 63 = 42

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3 years ago

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Which two ratios are equivalent to 10 : 12? 11:13 and 20:24 B. 10:12 and 11:13 C. 5:6 and 20:24

Readme [11.4K]

Answer: 5;6

Step-by-step explanation:

10 divided by 2 is 5

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3 years ago

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Mice21 [21]

Answer:

The answer is 2. Drag that in from the bottom to the right.

Step-by-step explanation:

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3 years ago

A positive integer from one to six is to be chosen by casting a die. Thus the elements c of the sample space C are 1, 2, 3, 4, 5

Alex_Xolod [135]

Answer with Step-by-step explanation:

We are given that six integers 1,2,3,4,5 and 6.

We are given that sample space

C={1,2,3,4,5,6}

Probability of each element= $\frac{1}{6}$

We have to find that $P(C_1),P(C_2),P(C_1\cap C_2) \;and\; P(C_1\cup C_2)$

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$C_1$ ={1,2,3,4}

Number of elements in $C_1$ =4

$P(E)=\frac{number\;of\;favorable \;cases}{Total;number \;of\;cases}$

Using the formula

$P(C_1)=\frac{4}{6}=\frac{2}{3}$

$C_2$ ={3,4,5,6}

Number of elements in $C_2$ =4

$P(C_2)=\frac{4}{6}=\frac{2}{3}$

$C_1\cap C_2$ ={3,4}

Number of elements in $(C_1\cap C_2)=2$

$P(C_1\cap C_2)=\frac{2}{6}=\frac{1}{3}$

$C_1\cup C_2=$ {1,2,3,4,5,6}

$P(C_1\cup C_2)=\frac{6}{6}=1$

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3 years ago