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Leni [432]
3 years ago
11

Find the product.........................

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0

Answer:

B


Step-by-step explanation:


<u>To find the answer, you have to </u><u>multiply each term of the first parenthesis' expression with each term in the next parenthesis' expression.</u><u> Then </u><u>combine like terms</u><u>.</u> So we have:


(6x^2-6x-5)(7x^2+6x-5)\\=(6x^2)(7x^2)+(6x^2)(6x)+(6x^2)(-5)+(-6x)(7x^2)+(-6x)(6x)+(-6x)(-5)+(-5)(7x^2)+(-5)(6x)+(-5)(-5)\\=42x^4+36x^3-30x^2-42x^3-36x^2+30x-35x^2-30x+25\\=42x^4-6x^3-101x^2+25


Answer choice B is right.

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Convert 230 Fahrenheit to celsius ​
Ber [7]

Answer:

110

Step-by-step explanation:

We can use the ratio from Fahrenheit to Celcius

32:0

Now just divide

230 ÷ 32

110

And That is your Celsius!

Hope this helps!

Have a nice day!

If you find my answer helpful

<em>Pls consider marking my answer as </em><em>Brainliest</em><em>! It would mean a lot!</em>

8 0
3 years ago
Please help with this
Anna [14]
The answer is 6f+(-6.1)
3 0
2 years ago
Read 2 more answers
The city of Orlando’s building a dog park in downtown Orlando dog park will be triangular shaped as shown on the coordinate plan
kiruha [24]

Answer:

Perimeter of the dog park = 15.4 yards

Step-by-step explanation:

Coordinates of the vertices of the given triangle are,

P(1, 2), Q(1, 6), R(-4, 2)

Since distance between the two points (x_1, y_1) and (x_2,y_2) is,

d = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Length of PQ = \sqrt{(1-1)^2+(2-6)^2}

PQ = 4

Length of PR = \sqrt{(1+4)^2+(2-2)^2}

PR = 5

Length of QR = \sqrt{(1+4)^2+(6-2)^2}

QR = \sqrt{25+16}

     = \sqrt{41}

     = 6.4 yards

Therefore, perimeter of the given triangle = PQ + QR + PR

                                                                       = 4 + 6.4 + 5

                                                                       = 15.4 yards

4 0
4 years ago
That's the question ?? ​
Oksanka [162]

Step-by-step explanation:

Before we answer, the area of a Circle given it radius is

a = \pi r {}^{2}

The area of a circle given it diameter is

a =  \pi( \frac{d}{2} ) {}^{2}

So let answers question 1-4.

1. The area is

1024\pi

2. The area is

576\pi

3.

1.225\pi

4.

309.76\pi

For the 5th problem, circumference is

\pi \times d

where d is the diameter and

2\pi  r

where r is the radius.

A circumference of 100 m means the radius is 50 because

2\pi \times r = 100\pi

r = 50

So this means the area is

2500 {\pi}

3 0
3 years ago
If f(x)=|x+2| is changed to g(x)=3f(x)+4, how is the graph of the function transformed?
frozen [14]

Answer:

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3 0
3 years ago
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