Given:
A fourth-degree polynomial function has zeros 4, -4, 4i , and -4i .
To find:
The fourth-degree polynomial function in factored form.
Solution:
The factor for of nth degree polynomial is:

Where,
are n zeros of the polynomial.
It is given that a fourth-degree polynomial function has zeros 4, -4, 4i , and -4i. So, the factor form of given polynomial is:


![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)
On further simplification, we get

![[\because i^2=-1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20i%5E2%3D-1%5D)
Therefore, the required fourth degree polynomial is
.
Neither parallel nor perpendicular
Identify first the common difference of the arithmetic sequence by the following,
d = (a22 - a1) / 22 - 1
d = (-226 - 26) / 22 -1 = -12
Solving for the 31st term,
a31 = a1 + (n - 1)d
a 31 = 26 + (31 - 1)(-12)
a 31 = -334
Therefore, the answer is letter A. -334.
18 dollars and 30 cents for 15 golf balls
Answer:
13760
Step-by-step explanation: