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Leni [432]
2 years ago
11

Find the product.........................

Mathematics
1 answer:
allochka39001 [22]2 years ago
6 0

Answer:

B


Step-by-step explanation:


<u>To find the answer, you have to </u><u>multiply each term of the first parenthesis' expression with each term in the next parenthesis' expression.</u><u> Then </u><u>combine like terms</u><u>.</u> So we have:


(6x^2-6x-5)(7x^2+6x-5)\\=(6x^2)(7x^2)+(6x^2)(6x)+(6x^2)(-5)+(-6x)(7x^2)+(-6x)(6x)+(-6x)(-5)+(-5)(7x^2)+(-5)(6x)+(-5)(-5)\\=42x^4+36x^3-30x^2-42x^3-36x^2+30x-35x^2-30x+25\\=42x^4-6x^3-101x^2+25


Answer choice B is right.

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Find the​ fourth-degree polynomial function with zeros 4​, -4, 4i ​, and -4i . Write the function in factored form.
Iteru [2.4K]

Given:

A fourth-degree polynomial function has zeros 4​, -4, 4i ​, and -4i .

To find:

The fourth-degree polynomial  function in factored form.

Solution:

The factor for of nth degree polynomial is:

P(x)=(x-a_1)(x-a_2)...(x-a_n)

Where, a_1,a_2,...,a_n are n zeros of the polynomial.

It is given that a fourth-degree polynomial function has zeros 4​, -4, 4i ​, and -4i. So, the factor form of given polynomial is:

P(x)=(x-4)(x-(-4))(x-4i)(x-(-4i))

P(x)=(x-4)(x+4)(x-4i)(x+4i)

P(x)=(x-4)(x+4)(x^2-(4i)^2)           [\because a^2-b^2=(a-b)(a+b)]

On further simplification, we get

P(x)=(x-4)(x+4)(x^2-4^2i^2)

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Therefore, the required fourth degree polynomial is P(x)=(x-4)(x+4)(x^2+16).

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Identify first the common difference of the arithmetic sequence by the following,
 
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Solving for the 31st term, 
 
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                                       a 31 =  -334

Therefore, the answer is letter A. -334. 




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