3 years ago

Find the product.........................

Mathematics

1 answer:

allochka39001 [22]3 years ago

6 0

Answer:

Step-by-step explanation:

To find the answer, you have to multiply each term of the first parenthesis' expression with each term in the next parenthesis' expression. Then combine like terms. So we have:

$(6x^2-6x-5)(7x^2+6x-5)\\=(6x^2)(7x^2)+(6x^2)(6x)+(6x^2)(-5)+(-6x)(7x^2)+(-6x)(6x)+(-6x)(-5)+(-5)(7x^2)+(-5)(6x)+(-5)(-5)\\=42x^4+36x^3-30x^2-42x^3-36x^2+30x-35x^2-30x+25\\=42x^4-6x^3-101x^2+25$

Answer choice B is right.

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How many grams of an alloy containing 25% silver should be melted with 50 grams of an alloy containing 60% silver in order to ob

Kipish [7]

Answer:

20 grams of an alloy containing 25% silver has to be melted with 50 grams of an alloy containing 60% silver to obtain a final alloy containing 50% silver

Step-by-step explanation:

We define

$A_{a}=50g @ 60\%$ , wich means alloy a has 50 grams containing 60% silver.

$A_{b}=xg @ 25\%$ , wich means alloy b has x grams containing 25% silver.

So we can build an equiation $50 \times 0.60+x \times 0.25=\frac{1}{2}(50+x)$ , as half of the final alloy has to be silver. Then solving for x

$30+0.25x=25+0.5x\\30-25=0.5x-0.25x\\5=0.25x\\x=\frac{5}{0.25}=20$

Wich means 20 grams of an alloy containing 25% silver ( $A_{b}$ ) has to be melted with 50 grams of an alloy containing 60% silver ( $A_{a}$ ) to obtain a final alloy containing 50% silver.