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denis-greek [22]
3 years ago
7

Convert 1.8 decimeters to millimeters​

Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0

Answer:

180 millimeters

Step-by-step explanation:

There are 100 millimeters in a decimeter

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A survey of high school juniors found the 75% of the students plan on attending college. If you pick 3 students at random, what
olya-2409 [2.1K]

Assuming you pick 3 students at random, The probability that at least two plan on attending college is 84%.

<h3>Probability</h3>

Using Binomial Distribution

Given:

n = 3

p = 0.75

q = 1-0.95 = 0.25

Hence:

P[≥2] = P[2] + P[3]=(3c2 ×0.75²×0.25) + 0.75³

P[≥2] = P[2] + P[3]=0.421875+0.421875

P[≥2] = P[2] + P[3]=0.84375×100

P[≥2] = P[2] + P[3]=84% (Approximately)

Inconclusion the probability that at least two plan on attending college is 84%.

Learn more about probability here:brainly.com/question/24756209

4 0
2 years ago
Please help me out thank you.​
s2008m [1.1K]

its A

Step-by-step explanation:

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3 years ago
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What’s the algebraic expression for this
Julli [10]

Answer:

1 3 6 10 15

Step-by-step explanation:

brainliest plz

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If someone was born in 2018 September 12th how old will they be in 2082?
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Find a particular solution to y" - y + y = 2 sin(3x)
leonid [27]

Answer with explanation:

The given differential equation is

y" -y'+y=2 sin 3x------(1)

Let, y'=z

y"=z'

\frac{dy}{dx}=z\\\\d y=zdx\\\\y=z x

Substituting the value of , y, y' and y" in equation (1)

z'-z+zx=2 sin 3 x

z'+z(x-1)=2 sin 3 x-----------(1)

This is a type of linear differential equation.

Integrating factor

     =e^{\int (x-1) dx}\\\\=e^{\frac{x^2}{2}-x}

Multiplying both sides of equation (1) by integrating factor and integrating we get

\rightarrow z\times e^{\frac{x^2}{2}-x}=\int 2 sin 3 x \times e^{\frac{x^2}{2}-x} dx=I

I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx -\int \frac{2\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx-\frac{2I}{3}\\\\\frac{5I}{3}=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{3}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{3} dx\\\\I=\frac{-2\cos 3x e^{\fra{x^2}{2}-x}}{5}+\int\frac{2x\cos 3x e^{\fra{x^2}{2}-x}}{5} dx

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3 years ago
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