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Ierofanga [76]
2 years ago
14

Please help me I’m failing!!!

Mathematics
2 answers:
zavuch27 [327]2 years ago
6 0
-9 is the answer hope you pass
tensa zangetsu [6.8K]2 years ago
6 0
-9 Is The Answer Hope This Helps
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Richard has a huge barn, 20 chickens, 4 ducks, 8 pigs, 6 horses, 4 cows, 8 ducks, and 4 goats. Which of the following equivalent
Triss [41]

2:3

ratio of cows to horses:

4:6 = 2:3

3 0
3 years ago
Points R, T, S, and Q are
Sladkaya [172]
Neither collinear nor coplanar.
All of the points would have to be on the same line to make them collinear, and they would also have to be on the same plane to make them coplanar. We can see in the diagram that not all of the points are on a line, and that some are at different heights than others.
6 0
3 years ago
The manager of a store that specializes in selling tea decides to experiment with a new blend. She will mix some Earl Grey tea t
amid [387]
The new tea is 75% Earl Grey and 25% Orange Pekoe.
$4 / pound times 75% = $3
$2 / pound times 25% = $0.5
$3 + $0.5 = $3.50 / pound

600 pounds times 75% = 450 pounds of Earl Grey
600 pounds times 25% = 150 pounds of Orange Pekoe
5 0
3 years ago
Round 0.978 to the nearest tenth
Setler79 [48]
The answer is one, because the number seven in the hundredths column is greater than five so you round the nine up to 1.0.
5 0
3 years ago
Solve the system of eqautions <br> y=x2-5x+7 , y=2x+1
IgorC [24]

Answer:

Step-by-step explanation:

The system of equations is given as

y=x^2-5x+7 - - - - - - - - - - 1

y=2x+1 - - - - - - - - - - - - - - 2

We would equate equation 1 to equation 2, it becomes

x^2-5x+7 = 2x+1

x^2-5x+7- 2x - 1 = 0

x^2-5x+7- 2x - 1 = 0

x^2 - 5x - 2x + 7 - 1 = 0

x^2 - 7x + 6 = 0

We would use the factorization method of solving quadratic equations.

x^2 - 6x - x + 6 = 0

x(x - 6) - 1(x - 6)

(x - 6)(x - 1) = 0

x - 6 = 0 or x - 1 = 0

x = 6 or x = 1

Substituting both values of x into equation 2, it becomes

For x = 6,

y=2×6 + 1 = 12 + 1 = 13

y = 13

For x = 1,

y=2 × 1 +1 = 2 + 1 = 3

y = 3

3 0
3 years ago
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