Polygons - here we just have triangles - are similar if the corresponding angles are congruent and the corresponding sides are in proportion. Polygons are congruent if in addition to corresponding angles be congruent, corresponding sides are congruent
Step-by-step explanation:
The discriminant of the quadratic equation
:

If Δ < 0, then the equation has two complex roots 
If Δ = 0, then the equation has one repeated root ![x=\dfrac{-b}{2a}[/tex If Δ > 0, then the equation has two discint roots [tex]x=\dfrac{-b\pm\sqrt\Delta}{2a}](https://tex.z-dn.net/?f=x%3D%5Cdfrac%7B-b%7D%7B2a%7D%5B%2Ftex%20%3C%2Fp%3E%3Cp%3EIf%20%CE%94%20%3E%200%2C%20then%20the%20equation%20has%20two%20discint%20roots%20%5Btex%5Dx%3D%5Cdfrac%7B-b%5Cpm%5Csqrt%5CDelta%7D%7B2a%7D)




10•8=80
so something times 80 will equal 400
80•5=400
They are right except for 12. i think it is C but i could be wrong.
Answer:
(f - g)(x) = -x² + 3x + 5
General Formulas and Concepts:
<u>Pre-Algebra</u>
<u>Algebra I</u>
- Function Notation
- Combining Like Terms
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 3x + 5
g(x) = x²
(f - g)(x) is f(x) - g(x)
<u>Step 2: Find (f - g)(x)</u>
- Substitute: (f - g)(x) = 3x + 5 - x²
- Rewrite: (f - g)(x) = -x² + 3x + 5