All categories

3 years ago

If ______, then ∆ABC and ∆EFD are congruent by the ASA criterion.

Mathematics

2 answers:

damaskus [11]3 years ago

7 0

The <em><u>correct answers</u></em> are:

Angle A is congruent to angle E; and BC=FD.

Explanation:

For ASA, we want two angles and an included side of one triangle congruent to two angles and an included side of the other triangle. The sides we have marked are AC and DE; the angles already marked congruent are C and D. In order to be ASA, the other angle must be on the other side of the congruent side; this means that we have angles A and E.

For SAS, we want two sides and an included angle of one triangle congruent to two sides and an included angle of the other triangle. We have angles C and D congruent and sides AC and DE congruent. In order to be SAS, the other side must be on the other side of the congruent angle; this means we have sides BC and FD.

Nat2105 [25]3 years ago

3 0

1.) If angle A is congruent to angle E, then ∆ABC and ∆EFD are congruent by the ASA criterion.
2.) If BC=FD, then ∆ABC and ∆EFD are congruent by the SAS criterion.

You might be interested in

It takes 32 hours for a motorboat moving downriver to get from pier A to pier B. The return journey takes 48 hours. How long doe

lina2011 [118]

Answer:

Time taken by the un powered raft to cover this distance is T = 192.12 hr

Step-by-step explanation:

Let speed of boat = u $\frac{km}{hr}$

Speed of current = v $\frac{km}{hr}$

Let distance between A & B = 100 km

Time taken in downstream = 32 hours

$32 = \frac{100}{u +v}$

$u + v = \frac{100}{32}$

u + v = 3.125 ------ (1)

Time taken in upstream = 48 hours

$48 = \frac{100}{u -v}$

$u -v = \frac{100}{48}$

u - v = 2.084 ------- (2)

By solving equation (1) & (2)

u = 2.6045 $\frac{km}{hr}$

v = 0.5205 $\frac{km}{hr}$

Now the time taken by the un powered raft to cover this distance

$T = \frac{100}{v}$

Because un powered raft travel with the speed of the current.

$T = \frac{100}{0.5205}$

T = 192.12 hr

Therefore the time taken by the un powered raft to cover this distance is

T = 192.12 hr

3 0

3 years ago

Read 2 more answers

Dennis and Ivy share some sweets between them in the ratio 7:4 Dennis got 42 sweets. How many does ivy get

MrRa [10]

Answer:

$Ivy = 24$

Step-by-step explanation:

Given

$Dennis : Ivy = 7 : 4$

Required

Determine the amount of sweet Ivy gets when Dennis = 42

We have:

$Dennis : Ivy = 7 : 4$ and

$Dennis = 42$

Substitute 42 for Dennis in $Dennis : Ivy = 7 : 4$

$42 : Ivy = 7 : 4$

Convert to fraction

$\frac{42}{Ivy} = \frac{7}{4}$

Cross Multiply:

$Ivy * 7 = 42 * 4$

Divide through by 7

$\frac{Ivy * 7}{7} = \frac{42 * 4}{7}$

$Ivy = \frac{42 * 4}{7}$

$Ivy = 6* 4$

$Ivy = 24$

6 0

2 years ago

In 1934 there was an extreme drought and the Great Plains and the number 1,934 is the value of the nine and the hundredth place

WARRIOR [948]

It should be noted that No. the value of the 9 in the hundred place is not ten times the value of 3 in the tens place.

<h3>How to illustrate the information?</h3>

It should be noted that the value of 3 in 1934 is 30 and the value of 9 is 900.

1934 = 1000 + 900 + 30 + 4

Therefore the value of 9 will be:

= 30 × 3

Therefore, the the value of the 9 in the hundred place is 30 times the value of 3 in the tens place.

Learn more about place values on:

brainly.com/question/2041524

#SPJ1

5 0

1 year ago

How do you tell if an equation is linear or not????

Tasya [4]

You can tell if the equation is linear or not if the equation makes a straight line on a graph.

3 0

2 years ago

Read 2 more answers

Which expression is equivalent??? help!

dexar [7]

Answer:

The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

Step-by-step explanation:

Given:

$\sqrt[3]{256x^{10}y^{7} }$

Solution:

We will see first what is Cube rooting.

$\sqrt[3]{x^{3}} = x$

Law of Indices

$(x^{a})^{b}=x^{a\times b}\\and\\x^{a}x^{b} = x^{a+b}$

Now, applying above property we get

$\sqrt[3]{256x^{10}y^{7} }=\sqrt[3]{(4^{3}\times 4\times (x^{3})^{3}\times x\times (y^{2})^{3}\times y )} \\\\\textrm{Cube Rooting we get}\\\sqrt[3]{256x^{10}y^{7} }= 4\times x^{3}\times y^{2}(\sqrt[3]{4xy}) \\\\\sqrt[3]{256x^{10}y^{7} }= 4x^{3}y^{2}(\sqrt[3]{4xy})$

∴ The equivalent expression for the given expression $\sqrt[3]{256x^{10}y^{7} }$ is

$4x^{3} y^{2}(\sqrt[3]{4xy} )$

5 0

3 years ago