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nikklg [1K]
3 years ago
7

Wat do I do I don't know

Mathematics
1 answer:
pshichka [43]3 years ago
3 0
I can't see all the triangles, but basically, it is asking you to write down triangles that are congruent with each other.

The marks in the corner of the triangle indicate that the angles of that triangle are congruent to the other triangle.

So,

Triangle NOP= Triangle NQP

Make sure that the points align with each other, otherwise you could be saying that two different triangles are congruent to each other. 

N= N   O=Q  P=P  

I hope this cleared some confusion! 
~kaikers
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In a school with 200 students, 45% are males. how many males are there.? please help me​
LUCKY_DIMON [66]

Answer:

<u><em>90 males.</em></u>

Step-by-step explanation:

To find the answer we will <u><em>divide 45% by 100</em></u>, and we get <u><em>0.45</em></u>.  Now <u><em>multiply 0.45 by 200</em></u> and you get <u><em>90</em></u>.  Therefore, <u><em>90 males is the answer. </em></u>

7 0
3 years ago
Find the value of x<br> a) 1<br> b) 31<br> c) 24<br> d) 14
Furkat [3]

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<em>H</em><em>ope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>you</em>

<em>Good</em><em> </em><em>luck</em><em> </em><em>on</em><em> </em><em>your</em><em> </em><em>assignment</em>

6 0
2 years ago
Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

6 0
3 years ago
Jayla had a bake sale to raise money. At the end of the day, she had 2 1/ 4 apple pie, 2/ 4 lemon pie, and 1 3 /4 cherry pie lef
irina1246 [14]

Answer:

4 2/4 or 4 1/2

Step-by-step explanation:

2 1/4+1 3/4

If you take 3/4 and add it to 1/4 you get 1 then you at 1+1+2=4 then you add the lemon ie which is 2/4, therefore, the answer is 4 2/4 or 4 1/2(simplified).

8 0
2 years ago
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