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kozerog [31]
3 years ago
11

Pls help Evaluate. [120 + (12 ÷ 3 • 30)] ÷ 20 + 102

Mathematics
1 answer:
sleet_krkn [62]3 years ago
4 0
The answer is 114. Here’s what I did.

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Please help me I dont get this :( number 4
jonny [76]
[x = amount earning 6% annually.]
(8000-x) = amount earning 15% annually
Then we set up our equation which is a sum of the 15% return and the 6% return and we let that sum equal our desired return on investment ($930). Then solve for x.
(8000-x)*.15 + x*.06 = 930
1200 - .15x + .06x = 930
.09x = 270
x = 3000.
Therefore, you should invest $3000 at 6% and $5000 at 15% to earn $930 annually.
4 0
3 years ago
Calculate 4 and 3/4 divided by 2 and 5/12
sp2606 [1]

Answer:1.965517241

Step-by-step explanation:

6 0
3 years ago
Which of the following correctly shows the distributive property?
exis [7]
D
4(x+5) = (4)(x)+(4)(5)
6 0
3 years ago
How do you put 943,261,586 with base ten numbers
Citrus2011 [14]

Answer:

(9 \times 10^{8}) + (4 \times 10^{7}) + (3 \times 10^{6}) + (2 \times 10^{5}) +  (6 \times 10^{4}) +  (10^{3}) +  (5 \times 10^{2}) +  (8 \times 10) + (6 \times 10^{0})

Step-by-step explanation:

How do you put 943,261,586 with base ten numbers

943,261,586  =  

900,000,000 + 40,000,000 + 3,000,000 + 200,000 + 60,000 + 1,000 + 500 + 80 +6 =

(9 \times 10^{8}) + (4 \times 10^{7}) + (3 \times 10^{6}) + (2 \times 10^{5}) +  (6 \times 10^{4}) +  (10^{3}) +  (5 \times 10^{2}) +  (8 \times 10) + (6 \times 10^{0})

8 0
3 years ago
The heights of women aged 20 to 29 are approximately normal with mean 64 inches and standard deviation 2.7 inches. Men the same
san4es73 [151]

Answer:

Step-by-step explanation:

Z=\frac{x-mu}{\sigma }

X - Heights of women aged 20 to 29: X is N(64, 2.7)

Y - Heights of men aged 20 to 29: X is N(69.3, 2.8)

a) X=6'=72"

Z=\frac{72-64}{2.7} =2.963

b) Y = 72"

z=\frac{72-69.3}{2.8} =0.965

c) 72' women can be taken as very tall but men moderately taller than average

d) Y<5'5" =65"

Z<\frac{65-69.3}{2.8} =-1.536

e) X>73"

Z>\frac{73-64}{2.7} =3.33

Almost 0% can be taken

f) IQR =Q3-Q1

Z scores =

5 0
3 years ago
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