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3 years ago

If a linear system has no solution what happens when you try to solve the system by adding or subtracting

1 answer:

7 0

In the addition/subtraction method, the two equations in the system are added or subtracted to create a new equation with only one variable. In order for the new equation to have only one variable, the other variable must cancel out. In other words, we must first perform operations on each equation until one term has an equal and opposite coefficient as the corresponding term in the other equation.

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-37 ≥ n - 20 What could n be??

sertanlavr [38]

Answer:

-78

Step-by-step explanation:

-78 - 20 = -98 which is less than -37,

im sorry this answer might be wrong i tried my best

6 0

3 years ago

Read 2 more answers

How many times as great as 10% is 100%?

monitta

It is 10 times greater because

10x10=100

8 0

3 years ago

Read 2 more answers

Apply division algorithm to find the quotient and remainder on dividing the polynomial 3 x^ + 4 x^ square + 6 x + 9 by x^ + 3x +

Ulleksa [173]

I suppose you mean

$\dfrac{3x^3+4x^2+6x+9}{x^2+3x+7}$

$3x^3=3x\cdot x^2$ , and if we multiply $x^2+3x+7$ by $3x$ we get $3x^3+9x^2+21x$ . Subtracting this from the numerator gives a remainder of $-5x^2-15x+9$ .

$-5x^2=-5\cdot x^2$ , and multiplying $x^2+3x+7$ by $-5$ gives $-5x^2-15x-35$ . Subtracting this from the previous remainder gives a new remainder of $44$ .

$44$ has no remaining factors of $x^2$ in it, so we're done, and

$\dfrac{3x^3+4x^2+6x+9}{x^2+3x+7}=\underbrace{3x-5}_{\rm quotient}+\dfrac{\overbrace{44}^{\rm remainder}}{x^2+3x+7}$

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3 years ago

What is the difference in a length between a 1 1/4 and a 3/4 inch button

Tasya [4]

Answer:

Step-by-step explanation:

8 0

3 years ago

) One year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million. Suppose a samp

Nutka1998 [239]

Answer:

Probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

Step-by-step explanation:

We are given that one year, professional sports players salaries averaged $1.5 million with a standard deviation of $0.9 million.

Suppose a sample of 400 major league players was taken.

Let $\bar X$ = sample average salary

The z-score probability distribution for sample mean is given by;

Z = $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ ~ N(0,1)

where, $\mu$ = mean salary = $1.5 million

$\sigma$ = standard deviation = $0.9 million

n = sample of players = 400

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

So, probability that the average salary of the 400 players exceeded $1.1 million is given by = P( $\bar X$ > $1.1 million)

P( $\bar X$ > $1.1 million) = P( $\frac{ \bar X -\mu}{{\frac{\sigma}{\sqrt{n} } }} }$ > $\frac{ 1.1-1.5}{{\frac{0.9}{\sqrt{400} } }} }$ ) = P(Z > -8.89) = P(Z < 8.89)

Now, in the z table the maximum value of which probability area is given is for critical value of x = 4.40 as 0.99999. So, we can assume that the above probability also has an area of 0.99999 or nearly close to 1.

Therefore, probability that the average salary of the 400 players exceeded $1.1 million is 0.99999.

4 0

3 years ago