In radians:
To get 0, only one part of the multiplication needs to be zero for the whole thing to be zero. Thus we get 2 equations:
t=0, and cos(t)=0
for the first equation, it's pretty self-explanatory and sp we get 0 as one solution.
For the second equation, cos(pi/2) and cos(3pi/2) both equal 0 so both pi/2 and 3pi/2 are answers. Since there is no bound to this problem, the actual answer is:
(2Z+1)pi/2 and 0
(2Z+1) means all odd integers
Answer:
C.
Step-by-step explanation:
that number line has both -5 and -1. so, you can count the distance between -1 and 2. and count the distance between -5 and 2
We can find the slope from (y2-y1)/(x2-x1) . So (-3-6)/(6+2) = -9/8
Answer:
see explanation
Step-by-step explanation:
The excluded values are any values of x that make the function undefined
Given
![\frac{1}{(x+4)(x-2)(x-5)}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%28x%2B4%29%28x-2%29%28x-5%29%7D)
The denominator of the rational function cannot be zero as this would make it undefined. Equating the denominator to zero and solving gives the values that x cannot be.
(x + 4)(x - 2)(x - 5) = 0
Equate each factor to zero and solve for x
x + 4 = 0 ⇒ x = - 4
x - 2 = 0 ⇒ x = 2
x - 5 = 0 ⇒ x = 5
x = - 4, x = 2, x = 5 are the excluded values