Answer:
Options (A) and (D)
Step-by-step explanation:
We can write the given division as,
Option (A)
When (2x² + 6x - 8) is divided (x + 5), the remainder is 12.
True.
Option (B)
When (2x² + 6x - 8) is divided (x - 5), the remainder is 12.
False.
Option (C)
When x = 5,
2x² + 6x - 8 = 12
2(5)² + 6(5) - 8 = 50 + 30 - 8
= 72
False.
Option (D)
When x = -5,
2(-5)² + 6(-5) - 8 = 50 - 30 - 8
= 12
True.
Option (E)
(x - 5) is a factor of 2x² + 6x - 8
If (x - 5) is a factor value of 2x² + 6x - 8 should be zero.
False.
Option (F)
(x + 5) is a factor of 2x² + 6x - 8
If (x + 5) is a factor then by substituting x = -5 in the expression value should be zero.
But the value is 12.
False.
Answer:
5c+4=2(c-5)
opening the parentheses we get:
5c+4=2c-10
putting like terms together we get
5c-2c=-10-4
3c=-14
c=-14/3
so the answer would be A. C = - 4 2/3
There are 4 cups in a quart so he can pour 8 glasses of juice :p
Answer:
see explanation
Step-by-step explanation:
To find the x- intercepts set y = 0, that is
- 2x² - 9x + 5 = 0
To factorise the quadratic consider the factors of the product of the coefficient of the x² term and the constant term that sum to give the coefficient of the x- term.
product = - 2 × 5 = - 10 and sum = - 9
The factors are - 10 and + 1
Use these factors to split the middle term
- 2x² - 10x + x + 5 = 0 ( factor the first/second and third/fourth terms )
- 2x(x + 5) + 1(x + 5) ( factor out (x + 5) )
(x + 5)(- 2x + 1) = 0
equate each factor to zero and solve for x
x + 5 = 0 ⇒ x = - 5
- 2x + 1 = 0 ⇒ x = 
x-intercepts are x = - 5 and x =
Answer:
113.
Step-by-step explanation:
119 is divisible by 7.
117 is divisible by 3.
I think it's 113.
If you use your calculator to divide 113 by odd numbers up to 57 you can check if it is prime. You stop at 57 because 57*2 = 114. You need not divide by any number ending in 5 because 113 ends in 3.
I have done this and can't find a quotient that is a whole number so it must be prime (unless I've made a mistake!).
