2/3 times 1/3 please help
2 answers:
You might be interested in
From the circle geometry theorem, a tangent to a circle makes 90° angles with the radius of the circle.
RQ is perpendicular to QP
Triangle RQP is a right-angled triangle
by Pythagoras theorem
units (rounded to one decimal place)
RQ is perpendicular to QP
Triangle RQP is a right-angled triangle
by Pythagoras theorem
Answer:
The correct answer is: by <em>rule</em> ASA rule of congruence.
Step-by-step explanation:
First let us prove by rule ASA (rule of congruence).
<u>Congruent side:</u>
(Given)
<u>Congruent angles:</u>
1. By definition of perpendicular,
Also,
Therefore,
or you can say,
2. Common angle between is
In a nutshell, in ,
(Angle)
(Side)
(Angle)
are congruent to the following angle, side and angle of :
(Angle)
(Side)
(Angle)
Therefore, by ASA rule of congruence, we can say .
<em>Since both triangles are congruent</em>, the sides and
are also congruent.