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skad [1K]
3 years ago
12

Solve the equation or formula for the indicated variable s=6r^3t for t

Mathematics
2 answers:
jok3333 [9.3K]3 years ago
7 0

Answer: t = s/6r^3

Step-by-step explanation:

Hi, to answer this question we have to isolate the variable t.

s=6r^3t

Since 6r^3 is multiplying the variable t, we have to divide both sides by 6r^3

s/6r^3=6r^3 t / (6r^3)

Since 6r^3 is in both the numerator and denominator we can cancel both terms.

s/6r^3 = t

Finally:

t = s/6r^3

Feel free to ask for more if needed or if you did not understand something.

harina [27]3 years ago
4 0
This is the answer i cant type it so i just snipped it good luck!!!:)

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15 - (-3) - 4<br><br> -16<br><br> 22<br><br> -8<br><br> 14
uranmaximum [27]
In this equation, you have to treat the number in the bracket first on the basis of BODMAS
15 - [-3]- 4
Note that when two minuses come together the product is a plus sign.
15 +3 - 4
You have to add before you subract
18 - 4 =14
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8 0
3 years ago
If each side of a square grows 6 mm, the area of ​​the square is multiplied by 16. How long are the sides of the original square
Phoenix [80]

Answer:

2 mm

Step-by-step explanation:

Let x be the sides of the original square,

then the area of the original square is x^2

The sides of the new square is x + 6

The area is (x + 6)^2

Then (x + 6)^2 = 16*x^2

Take square root on both sides and get

x + 6 = 4x,

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so x = 2 mm

3 0
2 years ago
If one angle of a set of vertical angles measures 63°, the sum of the vertical angles is °?
algol13

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Step-by-step explanation:

7 0
3 years ago
2.
iren [92.7K]

Answer:

  • Part A: The price of fuel A is decreasing by 12% per month.

  • Part B: Fuel A recorded a greater percentage change in price over the previous month.

Explanation:

<u>Part A:</u>

The function     f(x)=2.27(0.88)^x     calculates the price of fuel A each month by multiplying the price of the month before by 0.88.

Month       price, f(x)

1                 2.27 (0.88) = 1.9976 ≈ 2.00

2                2.27(0.88)² = 1.59808 ≈ 1.60

3                2.27(0.88)³ = 1.46063 ≈ 1.46

Then, the price of fuel A is decreasing.

The percentage per month is (1 - 0.88) × 100 = 12%, i.e. the price decreasing by 12% per month.

<u>Part B.</u>

<u>Table:</u>

m       price, g(m)

1          3.44

2         3.30

3          3.17

4         3.04

To find if the function decreases with a constant ration divide each pair con consecutive prices:

  • ratio = 3.30 / 3. 44 = 0.959 ≈ 0.96
  • ratio = 3.17 / 3.30 = 0.960 ≈ 0.96
  • ratio = 3.04 / 3.17 = 0.959 ≈ 0.96

Thus, the price of fuel B is decreasing by (1 - 0.96) × 100 =4%.

Hence, the fuel A recorded a greater percentage change in price over the previous month.

5 0
3 years ago
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