The measure of a leg of an isosceles triangle is twice the measure of its base. If the perimeter of the triangle is 64 units, wh
at is the measure of the base of the triangle?
A. 5.7 units
B. 12.8 units
C. 16.0 units
D. 21.3 units
A. 5.7 units
B. 12.8 units
C. 16.0 units
D. 21.3 units
1 answer:
You might be interested in
<h2>=>> <u>Solution (part A</u>) :</h2>
Given :
▪︎Triangle AMG is an isosceles triangle.
▪︎Measure of segment AM = (x+1.4) inches
▪︎Measure of segment MG = (2x+0.1) inches
▪︎Measure of segment AG = (3x-0.4) inches
▪︎segment AG is the base of triangle AMG.
Since AG is the base of the isosceles triangle AMG, segment AM and segment MG will be equal.
Which means :
Thus, the value of x = 1.3
Therefore :
▪︎The value of x = 1.3
<h2>=>> <u>Solution (Part B)</u> :</h2>We know that :
▪︎The value of x = 1.3
Which means :
The length of the leg AM :
Thus, the length of the leg AM = 2.7 inches
The length of leg MG :
Thus, the length of the leg MG = 2.7 inches
Since the measure of the two legs are equal (2.7=2.7), we can conclude that we have found out the correct length of each leg.
Therefore :
▪︎Measure of leg AM = 2.7 inches
▪︎Measure of leg MG = 2.7 inches
<h2>=>> <u>Solution </u><u>(</u><u>part C</u><u>)</u> :</h2>We know that :
Value of x = 1.3
Then, measure of the base AG :
Thus, the measure of the base = 3.5 inches
Therefore :
▪︎ the length of base AG = 3.5 inches.