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dangina [55]
3 years ago
6

PLEASE HELP ME SOLVE

Mathematics
1 answer:
jasenka [17]3 years ago
8 0

Two lines are perpendicular if their slope m and m' satisfy the equation

mm'=-1

The slope of the given line is 4, because the line is written in the slope-intercept y=mx+q, where m is the slope.

So, the perpendicular slope is

4m'=-1 \iff m'=-\dfrac{1}{4}

So, we want a line with slope -1/4 and passing through (-1,3). We can use the formula

y-b=m(x-a)

for the line passing trough (a,b) with slope m:

y-3=-\dfrac{1}{4}(x+1) \iff y=-\dfrac{1}{4}x-\dfrac{1}{4}+3\iff y=-\dfrac{1}{4}x+\dfrac{11}{4}

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