Question

PLEASE HELP ME SOLVE

Answer 1

Two lines are perpendicular if their slope m and m' satisfy the equation

$mm'=-1$

The slope of the given line is 4, because the line is written in the slope-intercept y=mx+q, where m is the slope.

So, the perpendicular slope is

$4m'=-1 \iff m'=-\dfrac{1}{4}$

So, we want a line with slope -1/4 and passing through (-1,3). We can use the formula

$y-b=m(x-a)$

for the line passing trough (a,b) with slope m:

$y-3=-\dfrac{1}{4}(x+1) \iff y=-\dfrac{1}{4}x-\dfrac{1}{4}+3\iff y=-\dfrac{1}{4}x+\dfrac{11}{4}$