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const2013 [10]
3 years ago
5

What is the slope of the line that passes through the points (2,3) and (-2,6)?

Mathematics
1 answer:
Kobotan [32]3 years ago
3 0

Answer:

-3/4

Step-by-step explanation:

To find the slope of the line, use the slope formula:

m = \frac{y_2-y_1}{x_2-x_1} = \frac{6-3}{-2-2} =\frac{3}{-2+-2}=\frac{3}{-4}

The slope of the line is -3/4.

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A system of inequalities is graphed below. The variable x represents the number of cans someone is buying, and y represents the
8090 [49]
We have that
<span>We will analyze each case to verify the answer
see the attached figure

</span>Point A) 7 cans and 140 bottles------------> (x,y)=(7,140)----> is not solution
Point B) 12 cans and 40 bottles------------> (x,y)=(12,40)----> is not solution
Point C) 8 cans and 120 bottles------------> (x,y)=(8,120)----> is a solution
Point D) 9 cans and 70 bottles------------> (x,y)=(9,70)-------> is a solution

the answer is
the solutions are
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6 0
2 years ago
1 - (9 – 4) : 5 =<br> Please someone help
Norma-Jean [14]

Answer:

-4 = 5

Step-by-step explanation:

9-4=5

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-4:5

3 0
3 years ago
Which is the correct second step for solving the equation (×+3)^2-4=18
Aleksandr-060686 [28]
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7 0
3 years ago
What is the vertex form of Y = x2 - 6x + 6?
ahrayia [7]

Answer:

\large\boxed{y=(x-3)^2-3}

Step-by-step explanation:

The vertex form of a quadratic equation <em>y = ax² + bx + c:</em>

<em>y = a(x - h)² + k</em>

(h, k) - coordinates of a vertex

We have the equation <em>y = x² - 6x + 6</em>.

Convert to the vertex form:

y=x^2-2(x)(3)+6\\\\y=\underbrace{x^2-2(x)(3)+3^2}_{(*)}-3^2+6\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\qquad(*)\\\\y=(x-3)^2-9+6\\\\y=(x-3)^2-3\to h=3,\ k=-3

7 0
2 years ago
शेळीच्या दुधा पासून बनवलेला दह्यासारखा पद्धत कोणता​
Naddik [55]
You spittin mad facts my guy
7 0
2 years ago
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