Answer:
\angle ACB=40^{\circ}, \angle ABC=63^{\circ}
Step-by-step explanation:
Finding x:
We know that 
, because it's a straight line. So, 
.
We know that the sum of the angles of any triangle will be 
.
So, we have that 
.
Combining like terms on the left gives 
.
Subtracting 
from both sides gives 
.
Dividing both sides by 
gives 
.
Finding missing angle measures:
.
.
So, 
and 
and we're done!
Note: 
. Coincidence? If not, try and prove it!
There is no picture so I can't help.
18 + 81 = 9(x²<span> + 6x + 9)
</span><span>11 = (x + 3)</span>²
When we are completing the square, we are going to move the value of c across the equals. We will do that by adding, and end up with
18=9(x²+6x)
We take the value of b (the coefficient of x), divide it by 2 and square it:
(6/2)²=3²=9
This is the value that completes the square. However, since the entire square is multiplied by 9, this value must be multiplied by 9 before we can add it across the equals:
18+9(9) = 9(x²+6x+9)
18+81=9(x²+6x+9)
99=9(x²+6x+9)
Dividing both sides by 9, we have:
11=x²+6x+9
11=(x+3)²
Try this solution:
Common view of the equation of the circle is (x-a)²+(y-b)²=r², where point (a;b) is centre of the circle, r - radius.
1. using the coordinates of the centre and point (2;13) it is possible to define the radius of the circle: r=√(5²+12²)=13;
the equation is (x+3)²+(y-1)²=13² or (x+3)²+(y-1)²=169;
2. using the coordinates of the centre and the radius: (x-2)²+(y-4)²=6² or (x-2)²+(y-4)²=36.
