11x-2 can you solve for xplzz

Select the correct answer. if you roll a single six-sided die, what is the probability of rolling an odd number? a. b. c. d. 3

Mamont248 [21]

Answer:

$\frac{1}{2}$

Step-by-step explanation:

P(odd number)= $\frac{3}{6}$

= $\frac{1}{2}$

5 0

2 years ago

What is the sum of 21 and 5 times a number f is 61

sukhopar [10]

Answer:

Answer is below

Step-by-step explanation:

21 + 5f = 61 Turn the words into an equation

-21 - 21 Subtract 21 from both sides

5f = 40 Divide both sides by 5

f = 8

If this answer is correct, please make me Brainliest!

5 0

3 years ago

Read 2 more answers

14 points :) Please answer fast! ;D

vova2212 [387]

Answer:

$x=2y+4$

Step-by-step explanation:

Let

x ------> the number of dogs Larry walked

y -----> the number of dogs Kyle walked

we know that

The linear equation that represent this scenario is equal to

$x=2y+4$

4 0

3 years ago

Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati

Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly selected, the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c. D. Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X $\sim$ N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

$P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})$

$P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})$

$P(X < 76) = P(Z< \dfrac{3}{12.5})$

$P(X < 76) = P(Z< 0.24)$

From the standard normal distribution tables,

$P(X < 76) = 0.5948$

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

$P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})$

$P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})$

$P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})$

$P( \overline X < 76) = P(Z< 1.2)$

From the standard normal distribution tables,

$P(\overline X < 76) = 0.8849$

c. Why can the normal distribution be used in part (b), even though the sample size does not exceed 30?

In order to determine the probability in part (b); the normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0

3 years ago

Math (10 points) please help

Valentin [98]

Answer:

Part 1. 50 and 17 denotes that he earns $50 for each shift he works at the dinner and $17 for each dog-walking job.

Variable x denotes the number of shifts at the dinner and y variable denotes the number of dog -walking job.

Part 2. The income from shift of work at the diner that is 50x, and the income from dog walking work that is 17y.

Part 3. The total income from the diner is given by 50x.

Step-by-step explanation:

Each week, Aubrey earns $50 for every shift he works at the diner and $17 for every dog-walking job.

He uses the expression (50x + 17y) to keep track of his earning.

Part 1. Here the coefficient of the expressions 50 and 17 denotes that he earns $50 for each shift he works at the dinner and $17 for each dog-walking job.

And the variable x denotes the number of shifts at the dinner and y variable denotes the number of dog -walking jobs.

Part 2. Therefore, there are two terms in the expression, one is the income from the shift of work at the diner that is 50x and the other is the income from dog walking work that is 17y.

Part 3. The total income from the diner is given by 50x. (Answer)

7 0

3 years ago