3xy
<span>y(3y)/3xy + y(xy)/3xy + (y+1)(3x)/3xy </span>
<span>NOW since all of the fractions have a denominator of 3xy, drop the denominators and solve using the numerators. </span>
<span>y(3y) + y(xy) + (y+1)(3x) </span>
<span>3y^2 + xy^2 + 3xy +3x </span>
<span>cannot simplify further.</span>
Answer:
Odd
Step-by-step explanation:
One way I remember is that:
Even functions: Have symmetry over the y-axis
Odd functions: Don't have symmetry over the y-axis
<span>14.62 super simple, good luck with any other questions!</span>
Answer:
C)16
Step-by-step explanation:
assuming the rhombus is named ABCD and E is where the diagonals meet.
Rhombus is a quadrilateral in which
- All sides are equal
- Opposite internal angles are equal
- Diagonals bisect each other at right angles
As rhombus is ABCD , AC is a diagonal which is bisected by E (According to the properties of Rhombus)
therefore AC will be twice of AE which is given to be 8
⇒ Answer is 16
The probability is 1/5 (or if you want it in decimals then it is 0.2) (if you want it in percent then it is 20%)
Hope that helped!!!
