Since a rhomubs is a 4 sided quadrilateral when parallel lines intersect within we solve for the triangles that are the result of the intersecting lines m<2=10, m<3=10
F(x) = 3x² + 6x - 1
The graph is a parabola open upward (a= 3>0) with a minimum.
Calculate the vertex:
x = -b/2a → x = -6/(2.3) = -1. Then the axis of symmetry is x = - 1
Now to calculate the minimum, plugin the value of x:
y = 3x² + 6x - 1
y = 3(-1)² + 6(-1) -1
y= 3 - 6 -1 and y = - 4,
Ten the vertex (minimum) is at (-1,- 4)
Answer:
Step-by-step explanation:
The inequality y - x < -3 should be solved for y, as follows:
Add x to both sides, obtaining:
y < x - 3
Note that this y < x - 3 has the form y = mx + b, which represents a straight line. In this case the straight line would be y = x - 3, meaning that the slope of this line is 1 and the y-intercept is -3.
Because y < x - 3 involves the inequality symbol <, draw a dashed line, not a solid line. The solution set consists of all points on the graph BELOW this dashed line y < x - 3.
Answer:
15 games
Step-by-step explanation:
12X3=36 5X3=15
So it means every 30 minutes he runs 6 miles
