Suppose a stat 121 professor would like to predict the mean final exam score of the students who obtained 80% on exam 3. What ki
1 answer:
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Answer:
5/18
Step-by-step explanation:
When two cubes are rolled there are 36 possibilities
Each dice has 6 equally like outcomes so possibilities are
(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)
(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)
(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)
(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)
(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)
(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)
Now we look at the pair that has sum equal to 9
(3,6) (4,5) (5,4) (6,3) that has sum of 9
Probability of sum is 9 =
we look at the pairs that has sum greater than 9
(4,6) (5,5)(5,6) (6,4)(6,5)(6,6)
Probability of sum greater than 9 =
Probability of sum 9 or higher = P(sum 9) + P(greater than 9)
=
You have to use PEMDAS.
