HI !
The lower quartile is 2
Answer C
Think of A as a constant - with D it's 117 and with M it's 88
So the difference between D and M is 29 (117-88)
We also know that M + D = 161
Let's substitute in the problem We will leave M equal to M and rewrite D as M+29 since it is 29 kg heavier.
M + M + 29 -161 or 2M +29 = 161 Subtracting 29 from both sides we get 2M=122
Now divide both sides two and get M=61
Since D is M+29 it is 61+29 or 100kg
Finally A + M = 88 A + 61 - 88 Subtract 61 from both sides and get A=17
So there you have it:
A=17kg
M=61kg
D=100kg and it works in all three equation in your problem (try it to check)
Answer:
Step-by-step explanation:
the right choice is C
you use c^2=a^2+b^2
where the largest side is the hypotenuse
It helps to imagine the variable a sort of as a unit. Like with 5 minus 12 lemons, it has no bearings on the addition/subtraction here.
Factor out a and subtract.