Only evens
1 answer:
Answer:
2. for the first equation, it works, for the second it doesnt so the answer is no
i cant graph for you, but its easy, just use y=mx+b m being the slope which is rise over run
8. x=6, y=-1
10. x=-5 y=5
this is all i could do in such a short notice, but i hope it helped you!
Step-by-step explanation:
for 8,
for 10,
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SA= Lateral Area + Area (of base)
Lateral area = perimeter of base x height
An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.
So 5 + 5 + square root of 50 is your perimeter
Multiply the perimeter times your height (8) and you get the lateral area.
Add your lateral area to the base area (triangle = 1/2 bh)
LA = 136.568...
Area of Triangle base = 12.5
Surface area = 149.068... square cm
Lateral area = perimeter of base x height
An isosceles triangle has two congruent base segments. The hypotenuse of an isosceles right triangle is (length of base segment) x (the square root of 2). I did the math for you (shown above) to get 5 as a base.
So 5 + 5 + square root of 50 is your perimeter
Multiply the perimeter times your height (8) and you get the lateral area.
Add your lateral area to the base area (triangle = 1/2 bh)
LA = 136.568...
Area of Triangle base = 12.5
Surface area = 149.068... square cm
Answer:
Step-by-step explanation:
The equations are:
The two graphs intersect when:
To find the area under the curve for the first equation:
To find the area under the curve for the second equation:
To find the total area:
Simplifying the equation:
Note: The reason the area is equal to the area two minus area one is that the line, area 2, is above the region of interest (see image).
