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nikklg [1K]
3 years ago
6

Only evens

Mathematics
1 answer:
VARVARA [1.3K]3 years ago
3 0

Answer:

2. for the first equation, it works, for the second it doesnt so the answer is no

i cant graph for you, but its easy, just use y=mx+b m being the slope which is rise over run


8. x=6, y=-1

10. x=-5 y=5

this is all i could do in such a short notice, but i hope it helped you!


Step-by-step explanation:

for 8, 2x-x+5=11\\x+5=11\\x=6

for 10,

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Evaluate the surface integral S F · dS for the given vector field F and the oriented surface S. In other words, find the flux of
slega [8]
 <span>Let r(x,y) = (x, y, 9 - x^2 - y^2) 

So, dr/dx x dr/dy = (2x, 2y, 1) 

So, integral(S) F * dS 
= integral(x in [0,1], y in [0,1]) (xy, y(9 - x^2 - y^2), x(9 - x^2 - y^2)) * (2x, 2y, 1) dy dx 
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3 years ago
a water sprinkler rotates one-degrer turn at each interval. if the sprinkler rotates a total 110, how many one turns has the spr
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3 years ago
The weekly sales of Honolulu Red Oranges is given by q = 990 − 22p. Calculate the price elasticity of demand when the price is $
elena55 [62]

Answer:

E = -2. The demand is going down by 2% per 1% increase in price at that price level.

The price that gives a maximum revenue is $22.5. The maximum revenue is $9112.5

Step-by-step explanation:

The overall demand formula: Q = aP + b

Q = 990 - 22P

<u>Demand elasticity:</u>

At P = $30, the Q = 990 - 22×30 = 330. a = \frac{dQ}{dP} = -22

The formula for demand elasticity: E = \frac{dQ}{dP}×\frac{P}{Q}

Demand elasticity at $30: E = -22 × \frac{30}{330} = -2

So, The demand will be going down by 2% if 1% increase in price.

<u>Revenue:</u>

R = P×Q = P×(990 - 22P) = -22P² - 990P

R' = -44P - 990. The revenue is maximum when R' = 0

⇔0 = -44P - 990 ⇔ P = $22.5

At the P = $22.5, the Q = 990 - 22×22.5 = 495.

The maximum revenue = $22.5×495 = $11,137.5

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3 years ago
X = ? ? ? ? ? ? ? ? ?
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Answer:

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Step-by-step explanation:

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