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AleksandrR [38]

3 years ago

8

Find the exponential function f(x)=Ca^x whose graph goes through the points (0,4) and (3,32).

1 answer:

kogti [31]3 years ago

8 0

We are given the exponential expression f(x) = Ca^x that should pass through the points (0,4) and (3,32). In this case, we first substitute the first point, (0,4) to the function to yield 4 = Ca ^0; hence Ca is equal to 4. The final expression hence is f(x) = 4^x

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Solve for x. thank you in advance, please answer my other questions as well im having a tough time

klio [65]

Answer:

$3/4$

Step-by-step explanation:

$log_{(5)} (\sqrt[4]{125})$

$\frac{log(\sqrt[4]{125}) }{log(5)}$

$=0.75$

8 0

3 years ago

PLEASE HELP AND EXPLAIN <br><br> Solve the following equation by factoring 2x^2 - x = 2-4x

Kruka [31]

Answer:

pls answer my newest question

3 0

3 years ago

Read 2 more answers

On a cold day, hailstones fall with a velocity of 2i − 6k m s−1 . If a cyclist travels through the hail at 10i m s−1 , what is t

Paraphin [41]

Answer:

The velocity of the hail relative to the cyclist is $V_{hc}=-8\hat{i}-6\hat{k}$

The angle at which hailstones falling relative to the cyclist is $\theta = 36.86^\circ$

Step-by-step explanation:

Given : On a cold day, hailstones fall with a velocity of $2\hat{i}-6\hat{k}\text{ m/s}$ . If a cyclist travels through the hail at $10\hat{i} \text{ m/s}$ .

To find : What is the velocity of the hail relative to the cyclist and At what angle are the hailstones falling relative to the cyclist?

Solution :

The velocity of the hailstone falls is $V_h=2\hat{i}-6\hat{k}\text{ m/s}$

The velocity of the cyclist travels through the hail is $V_c=10\hat{i} \text{ m/s}$

The velocity of the hail relative to the cyclist is given by,

$V_{hc}=V_h-V_c$

Substitute the value in the formula,

$V_{hc}=2\hat{i}-6\hat{k}-10\hat{i}$

$V_{hc}=-8\hat{i}-6\hat{k}$

So, The velocity of the hail relative to the cyclist is $V_{hc}=-8\hat{i}-6\hat{k}$

Now, The angle of hails falling relative to the cyclist is given by

$\theta = \tan^{-1}(\frac{-6}{-8})$

$\theta = \tan^{-1}(\frac{3}{4})$

$\theta = 36.86^\circ$

So, The angle at which hailstones falling relative to the cyclist is $\theta = 36.86^\circ$

4 0

4 years ago

Tara has two bags of marbles the first bag contains 8 red marbles four blue marbles three green marbles the second bag contains

Lesechka [4]

Answer:

2/27

Explanation:

The two events, drawing a blue marble out of each bag, are independent. This means to find the probability of both occurring, we multiply them.

In the first bag, there are 5 blue marbles out of 15 total. This makes the probability 5/15, or 1/3.

In the second bag, there are 2 blue marbles out of 9 total. This makes the probability 2/9.

Together, the probability of both events happening are:

1/3(2/9) = 2/27

5 0

3 years ago

PLS HELP<br><br> heres my question i pinned as a picture

Murrr4er [49]

Advanced ($10): A

Door ($13): D

Money: 10A + 13D = 544 ⇒ 1(10A + 13D = 544) ⇒ 10A + 13D = 544

Quantity: A + D = 46 ⇒ -10(A + D = 46) ⇒ <u> -10A - 10D</u> = <u>-460 </u>

3D = 84

D = 28

Quantity: A + D = 46 ⇒ A + (28) = 46 ⇒ A = 18

Answer: advanced = 18 people, at the door = 28 people

7 0

3 years ago