Find the equation of the line that passes through (1,3) and is perpendicular to y=2x−1. Leave your answer in the form y=mx+c

Mathematics

1 answer:

Ugo [173]3 years ago

5 0

Answer:

y = -1/2x + 3.5

Step-by-step explanation:

In order to pass through the point (1, 3), and is perpendicular to y = 2x - 1, then the line must be y = -1/2x + 3.5. Hope this helps!

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blondinia [14]

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Determine the x-intercept and the y-intercept for the graph of this equation:<br> 2x - 3y + 36 = 0

natali 33 [55]

QUESTION:- DETERMINE THE X-INTERCEPT AND THE Y-INTERCEPT FOR THE GRAPH OF THE EQUATION.

EQUATION:- 2x - 3y + 36 = 0

STANDARD EQUATION:- y=mx+c

where

m-> slope.
c-> Y-INTERCEPT
x&y are the coordinates.

SO GIVEN EQUATION:- 2x - 3y + 36 = 0

WE CAN SOLVE THIS TO CHANGE IN FORMAT OF STANDARD EQUATION

$2x - 3y + 36 = 0 \\ 2x + 36 =3y \\ y = \frac{2}{3} x + \frac{36}{3} \\ y = \frac{2}{3} x + \frac{ \cancel{36}^{ \: \: 12} }{ \cancel3} \\ y = \frac{2}{3} x + 12 \\$

SO :-

$m = \frac{2}{3} \\ y - intercept = 12 \: ans$

$slope = \frac{y2 - y1}{x2 - x1} \\ \frac{2}{3} = \frac{0 - 12}{x - 0} \\ 2x = ( - 12) \times 3 \\ x = \frac{ - \cancel{12}^{ \: \: 6} \times 3 }{ \cancel{2}} \\ x = - 18 \: \: ans$