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vovangra [49]
3 years ago
15

Tara has two bags of marbles the first bag contains 8 red marbles four blue marbles three green marbles the second bag contains

4 red marbles three blue marbles four green marbles Tara will randomly select 1 marble from the first bag and Replace it. Tara will randomly select 1 marble from the second bag and not replace it. What? Is the probability that Tara will select a blue Marble from each bag?
Mathematics
1 answer:
Lesechka [4]3 years ago
5 0

Answer:

2/27

Explanation:

The two events, drawing a blue marble out of each bag, are independent. This means to find the probability of both occurring, we multiply them.

In the first bag, there are 5 blue marbles out of 15 total. This makes the probability 5/15, or 1/3.

In the second bag, there are 2 blue marbles out of 9 total. This makes the probability 2/9.

Together, the probability of both events happening are:

1/3(2/9) = 2/27

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a store sells grass seed in small bags and large bags.the small bags have 7 pounds of seed for 27.93 and large bags cost 66.98.w
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Answer

Find out the ratio of price to pound for each bag.

To prove

As given

A store sells grass seed in small bags and large bags.the small bags have 7 pounds of seed for $27.93 .

7 pound = $27.93

Now find out the cost for the 1 pound.

1\ pound\ cost= \frac{27.93}{7}

1 pound cost = $3.99

As given large bags cost $66.98.

Now find out pounds in the large bags.

Let us assume that the number of pounds in the large bags be x.

Than

3.99 × x = 66.98

x = \frac{66.98}{3.99}

x = 16.8 pounds (approx)

Now find out the ratio of  price to pound for each bag.

As small bags weight = 7 pounds

Cost of the small bags = $27.93

\frac{Price\ of\ small\ bag}{Cost\ of\ the\ small\ bags} = \frac{27.93}{7}

As large bags weight = 16.8 pounds

Cost of the large bags = $66.98

\frac{Price\ of\ large\ bag}{Cost\ of\ the\ large\ bags} = \frac{66.98}{16.8}

Hence proved


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