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elixir [45]
3 years ago
5

How to create an equation for a circle​

Mathematics
1 answer:
adoni [48]3 years ago
5 0

°360

......................

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I need your help on this one pls its another one but different question<br> and please dont guess
Ainat [17]

Answer:

All except the second one (angle g is not similar to angle r)

Step-by-step explanation:

Just look at the order of the letters. It it's the same, its similar.

4 0
3 years ago
Sin(x+y)-sin(x-y)/cos(x+y)+cos(x-y)=tany<br> how do i verify this?
dsp73

Answer:

Step-by-step explanation:

Numerator

sin

x

cos

y

+

cos

x

sin

y

−

[

sin

x

cos

y

−

cos

x

sin

y

)

=

sin

x

cos

y

+

cos

x

sin

y

−

sin

x

cos

y

+

cos

x

sin

y

=

2

cos

x

sin

y

Denominator

cos

x

cos

y

−

sin

x

sin

y

+

cos

x

cos

y

+

sin

x

sin

y

=

cos

x

cos

y

−

sin

x

sin

y

+

cos

x

cos

y

+

sin

x

sin

y

=

2

cos

x

cos

y

---------------------------------------------------------------

left side can now be expressed as

2

cos

x

sin

y

2

cos

x

cos

y

=

2

cos

x

sin

y

2

cos

x

cos

y

=

sin

y

cos

y

and  

sin

y

cos

y

=

tan

y

=

right side hence proved

7 0
3 years ago
Combine Like Terms <br><br> 8 + 19t - 6t<br><br> A) 8 - 13t<br> B) 21<br> C) 21t<br> D) 8 + 13t
Hunter-Best [27]

Answer:

8 + 13t

Step-by-step explanation:

Since 19t and 6t have the same variables

4 0
3 years ago
Reduce the fraction -20t5u2v3 / 48t7u4v .
kondor19780726 [428]
Deal with the numbers and variables step by step 

-20/48  = -5/12
t5 / t7 = t^-2 = 1 /t2
u^2 / u^4 = u^-2 = 1/u^2
v^3 / v = v^2

so answer is      -5v^2 / 12t^2u^2
6 0
3 years ago
If triangle RST is within Quadrant 2 and csc T = 13/12, what is the value of cotT?
zhuklara [117]

Answer:

\boxed {cot T = -\frac{5}{12}}

Step-by-step explanation:

<u>Finding the missing side</u> :

  • x² = 13² - 12²
  • x² = 169 - 144
  • x = √25
  • x = 5

<u>Taking the cot value</u> :

  • cot T = adjacent / opposite
  • cot T = -5/12 (As cot is negative in Quadrant 2)
5 0
1 year ago
Read 2 more answers
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