3 years ago

Find the values of x and y.

Mathematics

1 answer:

Papessa [141]3 years ago

6 0

Step-by-step explanation:

x=20

y=100

solution in image

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ace car rental rents cars for x dollars per day plus y dollars for each mile driven carlos renteda car for a 4 days drove 100 mi

Yuliya22 [10]

$T=xd+ym\\x(4)+y(100)=(120)\\x(1)+y(240)=(80)\\\\4x+960y=320\\4x+100y=120\\860y=200\\y=\frac{200}{860}\\y=\frac{10}{43}\\\\x+240(\frac{10}{43})=80\\x+\frac{2400}{43}=\frac{3440}{43}\\x=\frac{1040}{43}$

x = 1040/43 = $24.19 per day.

y = 10/43 = $0.23 per mile.

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3 years ago

Solve for X. *<br> (1 Point)<br> x + 70<br> 76°<br> 410

Yuki888 [10]

Answer:

x = -7

Step-by-step explanation:

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2 years ago

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Why do you think you can prove congruency with SSS but not with AAA Property. Explain your answer with figures.

Anettt [7]

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3 years ago

an astronaut who weighs 126lb on earth weighs 21lb on the moon. How much would a person who weighs 25lb on the moon weigh on ear

irakobra [83]

If 21 Ib on moon=126 IB on earth
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3 years ago

HELP help HELP help HELP help HELP help HELP help HELP help HELP help

Morgarella [4.7K]

$\text{mass of freight train} = 9.98 \times {10}^{6} kg$

$\text{mass of aircraft carrier} = 7.3 \times {10}^{7} \: kg$

$\text{difference of masses of aircraft and train: } \\ \\ 7.3 \times {10}^{7} - 9.98 \times {10}^{6} \\ \\ = 73 \times {10}^{6} - 9.98 \times {10}^{6}$

$= (73 - 9.98 )\times {10}^{6} \\ \\ = 63.02 \times {10}^{6} \\ \\ = 6.302 \times {10}^{6} \: kg \\ \\ \approx 6.3 \times {10}^{6} \: kg$

Approximately, aircraft carrier is 6.3 × 10^6 kg heavier than the freight train.

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3 years ago