Drawing this square and then drawing in the four radii from the center of the cirble to each of the vertices of the square results in the construction of four triangular areas whose hypotenuse is 3 sqrt(2). Draw this to verify this statement. Note that the height of each such triangular area is (3 sqrt(2))/2.
So now we have the base and height of one of the triangular sections.
The area of a triangle is A = (1/2) (base) (height). Subst. the values discussed above, A = (1/2) (3 sqrt(2) ) (3/2) sqrt(2). Show that this boils down to A = 9/2.
You could also use the fact that the area of a square is (length of one side)^2, and then take (1/4) of this area to obtain the area of ONE triangular section. Doing the problem this way, we get (1/4) (3 sqrt(2) )^2. Thus,
A = (1/4) (9 * 2) = (9/2). Same answer as before.
Answer: I x^2 y^3 z
Step-by-step explanation:
This is the one most simplified. I’ll tell you why the others are incorrect.
F) 3^5 x^2 can be simplified. 3^5= 243. The simplified answer would be 243 x^2
G) (5y)^3= 125y^3
H) a^0 b (^0= 1 always) -> ab
Hope this helps!
Answer:
Step-by-step explanation:
Hope this helps!
Answer: 1400
Step-by-step explanation: you add 40 and 30 then you times it by 20 because it said " what is the area of the part that's painted blue" it's trying to throw you off by having the other numbers by the window and the door.
