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3 years ago

6

carter needs to wrap 7 presents. he lays the ribbon out flat and says ,if i nake 6 equally spaced cuts i'll have just enough pie

ces i can use 1 piece for each packages and i won't have any pieces left over .does he have enough pieces to wrap all the presents

1 answer:

Andrej [43]3 years ago

8 0

Yes he does. If you cut something 6 times you make 7 pieces

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Andrei [34K]

Answer:

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Step-by-step explanation:

4x+3y and 2x-y can be added to find result for the circle.

Let C1 represent circle 1

4x+3y+2x-y=C1\\

Combining\:like\:terms\\

4x+2x+3y-y=C1

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Now, We need to solve:

Let R1 represent rectangle 4

x+4y + R1 = 4x+5y

R1=4x+5y-(x+4y)

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So, Solving x+4y + R1 = 4x+5y, We get R1 = 3x+y

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Let C4= Circle 4

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Answer:

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$\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{c}a+2b\\b\\-3a\end{array}\right]=a\left[\begin{array}{c}1\\0\\-3\end{array}\right]+b\left[\begin{array}{c}2\\1\\0\end{array}\right]$

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