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never [62]
3 years ago
5

Enter a letter. Line is a transversal.

Mathematics
2 answers:
jarptica [38.1K]3 years ago
7 0

Answer:

c

Step-by-step explanation:

natita [175]3 years ago
4 0

Answer:

Line c

Step-by-step explanation:

Transversal means an intersecting a system of lines. The only line that intersects the parallel lines is line c so that is the transversal line.

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X=<br> A) 80<br> B) 90<br> C) 100
Sunny_sXe [5.5K]
X= A) 80 I believe you double 120 to 240 and divide by the 4 quarters.
6 0
4 years ago
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FOR BRAINLIEST! which expression is the simplest form of - (4x^3+x^2) + 2(x^3-3x^2)?
Setler [38]
Answer D

step by step
6 0
3 years ago
Factor the greatest common factor: −5k2 20k − 30. −1(5k2 − 20k 30) −5(k2 − 4k 6) −5k(k2 − 4k 6) −5(k2 4k − 6)
Leno4ka [110]

The greatest common factor−5k2 20k − 30 is  -5(k^{2} -4k-6).

<h3>What is meant by the greatest common factor?</h3>
  • The most common factor in mathematics is the highest number that may divide evenly into two other numbers.
  • The largest factor that splits both numbers is the greatest common factor. List the prime factors of each integer before calculating the greatest common factor. One 2 and one 3 are shared by those aged 18 and 24. We multiply them to obtain the GCF. Therefore the GCF for 18 and 24 is 2 * 3 = 6.
  • The biggest positive integer that divides evenly into all the numbers with no remainder is the greatest common factor (GCF, GCD, or HCF) of a collection of whole numbers.

To find the greatest common factor:

−5k2 20k − 30.

Factor the expression:   5(-k^{2} +4k-6)

Factor the expression:   5(-k^{2} -4k+6)

Multiply the monomials: 5(k^{2} +4k+6)

The greatest common factor: -5(k^{2} -4k-6).

The greatest common factor−5k2 20k − 30 is -5(k^{2} -4k-6).

To learn more about The greatest common factor, refer to:

brainly.com/question/219464

#SPJ4

7 0
2 years ago
Read 2 more answers
Create an equation using the table of values below.
djyliett [7]

Answer:

1.  y = 2x - 1

Step-by-step explanation:

See attached image.

7 0
2 years ago
Can someone help me with variable expressions
EastWind [94]
You get the product by multiplying...in this case you want to double the product of j and 8 so:

2(8*j)

2(8j)

16j
4 0
3 years ago
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