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4 years ago

Explain how linear equations can be used in temperature conversion.

Mathematics

1 answer:

IRISSAK [1]4 years ago

3 0

Answer:

It is important to know that linear equation can be used in temperature conversion using the formula C = (5/9)(F-32) - a converter for degrees Fahrenheit (°F) for temperature to degree Centigrade (°C)

Step-by-step explanation:

It is important to know that linear equation can be used in temperature conversion using the formula C = (5/9)(F-32) - a converter for degrees Fahrenheit (°F) for temperature to degree Centigrade (°C).

Lets take an example, if we have 81°F and want to convert in (°C). So, here is the procedure:

C = (5/9) (81 - 32)

= (5/9) (49)

= 27.22 °C

So, it is clear that linear equation can be used in temperature conversion using the formula C = (5/9)(F-32) - a converter for degrees Fahrenheit (°F) for temperature to degree Centigrade (°C).

Keywords: linear equation, converter, C = (5/9)(F-32)

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Natalie has 28 erasers. She divided some of her erasers equally among 3 friends. Natalie has 10 erasers left. How many erasers d

Korvikt [17]

Hey there! :D

Subtract 10 from 28.

28-10= 18

Now, divide that by 3. (for her three friends)

18/3= 6

Each friend got 6 erasers.

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8 0

4 years ago

Read 2 more answers

Which expression has the same value as 4÷25?

Hatshy [7]

Answer:

We need the choices, since there are plenty equations with the same value.

Step-by-step explanation:

4/25=0.16

Whichever equation equals 0.16 is your answer.

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4 years ago

Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in

Law Incorporation [45]

Answer:

(a) 900

(b) [567.35 , 1689.72]

(c) [23.82 , 41.11]

Step-by-step explanation:

We are given that a sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms i.e.;

Sample mean, $xbar$ = 290 Sample standard deviation, s = 30 and Sample size, n = 20

(a) Point estimate of the population variance is equal to sample variance, which is the square of Sample standard deviation ;

$\sigma^{2}$ = $s^{2}$ = $30^{2}$

$\sigma^{2}$ = 900

(b) 90% confidence interval estimate of the population variance is given by the pivotal quantity of $\frac{(n-1)s^{2} }{\sigma^{2} }$ ~ $\chi^{2} __n_-_1$

P(10.12 < $\chi^{2}__1_9$ < 30.14) = 0.90 {At 10% significance level chi square has critical

values of 10.12 and 30.14 at 19 degree of freedom}

P(10.12 < $\frac{(n-1)s^{2} }{\sigma^{2} }$ < 30.14) = 0.90

P( $\frac{10.12}{(n-1)s^{2} }$ < $\frac{1 }{\sigma^{2} }$ < $\frac{30.14}{(n-1)s^{2} }$ ) = 0.90

P( $\frac{(n-1)s^{2} }{30.14}$ < $\sigma^{2}$ < $\frac{(n-1)s^{2} }{10.12}$ ) = 0.90

90% confidence interval for $\sigma^{2}$ = $[\frac{19s^{2} }{30.14} , \frac{19s^{2} }{10.12}]$

= $[\frac{19*900 }{30.14} , \frac{19*900 }{10.12}]$

= [567.35 , 1689.72]

Therefore, 90% confidence interval estimate of the population variance is [567.35 , 1689.72] .

P( $\sqrt{\frac{(n-1)s^{2} }{30.14}}$ < $\sigma$ < $\sqrt{\frac{(n-1)s^{2} }{10.12}}$ ) = 0.90

90% confidence interval for $\sigma$ = $[\sqrt{\frac{19s^{2} }{30.14}} , \sqrt{\frac{19s^{2} }{10.12}} ]$

= [23.82 , 41.11]

Therefore, 90% confidence interval estimate of the population standard deviation is [23.82 , 41.11] .

7 0

3 years ago

Find the value of x. Round your answer to the nearest tenth.

skad [1K]

Answer:

x = 9.7

Step-by-step explanation:

Reference angle (θ) = 68°

Opposite = 24

Adjacent = x

Apply, the trigonometric function, TOA which is:

$tan (/theta) = \frac{Opp}{Adj}$

Plug in the values

$tan 68 = \frac{24}{x}$

Multiply both sides by x

$x*tan 68 = 24$

Divide both sides by tan 68

$x = \frac{24}{tan 68}$

x = 9.69662942

x = 9.7 (nearest tenth)

8 0

3 years ago

The length of a rectangle is 3 1/6 cm longer than the width. The perimeter of the rectangle is 15 1/3 cm. What are the width and

ahrayia [7]

The width of rectangle is $2\frac{1}{4}$ cm and length is $5\frac{5}{12}$ cm.

Step-by-step explanation:

Let,

Width of rectangle = w

Length of rectangle = $w+3\frac{1}{6}=w+\frac{19}{6}$

Perimeter of rectangle = $15\frac{1}{3}=\frac{46}{3}$ cm

Perimeter = 2(Length + Width)

$\frac{46}{3}=2(w+\frac{19}{6}+w)\\\\\frac{46}{3}=2(2w+\frac{19}{6})\\\\\frac{46}{3}=4w+\frac{19}{3}\\\\4w+\frac{19}{3}=\frac{46}{3}\\\\4w=\frac{46}{3}-\frac{19}{3}\\\\\ 4w=\frac{46-19}{3}\\\\4w=\frac{27}{3}\\\\4w=9$

Dividing both sides by 4

$\frac{4w}{4}=\frac{9}{4}\\\\w=\frac{9}{4}$

Width of rectangle = $\frac{9}{4}=2\frac{1}{4}\ cm$

$Length = w+\frac{19}{6}=\frac{9}{4}+\frac{19}{6}\\\\Length = \frac{27+38}{12}=\frac{65}{12}\\\\Length=5\frac{5}{12}\ cm$

The width of rectangle is $2\frac{1}{4}$ cm and length is $5\frac{5}{12}$ cm.

Keywords: rectangle, perimeter

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3 years ago