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Andreyy89
3 years ago
8

Could someone help me with this question

Mathematics
2 answers:
denis23 [38]3 years ago
8 0
Which question would that be
valkas [14]3 years ago
3 0
The question is number 17 because that is the only one that is completely shown
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Find the area of the figure.<br><br> PLS I NEED HELP FAST!
Rom4ik [11]

55 ft

base + base2 / 2 x h

8 0
3 years ago
The rectangular bar is connected to the support bracket with a 10-mm-diameter pin. The bar width is w = 70 mm and the bar thickn
german

Answer:

P_max = 9.032 KN

Step-by-step explanation:

Given:

- Bar width and each side of bracket w = 70 mm

- Bar thickness and each side of bracket t = 20 mm

- Pin diameter d = 10 mm

- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa

- Average allowable shear stress of pin S = 115 MPa

Find:

The maximum force P that the structure can support.

Solution:

- Bearing Stress in bar:

                                       T = P / A

                                       P = T*A

                                       P = (120) * (0.07*0.02)

                                       P = 168 KN

- Shear stress in pin:

                                        S = P / A

                                        P = S*A

                                        P = (115)*pi*(0.01)^2 / 4

                                        P = 9.032 KN

- Bearing Stress in each bracket:

                                       T = P / 2*A

                                       P = T*A*2

                                       P = 2*(120) * (0.07*0.02)

                                       P = 336 KN

- The maximum force P that this structure can support:

                                      P_max = min (168 , 9.032 , 336)

                                      P_max = 9.032 KN

3 0
3 years ago
Write y=2x^2+12x+14 In vertex form
ratelena [41]

Answer:

\large\boxed{y=2(x+3)^2-6}

Step-by-step explanation:

The vertex form of a parabola f(x) = ax² + bx + c:

y=a(x-h)^2+k

(h, k) - vertex

h=\dfrac{-b}{2a}\\\\k=f(h)

We have the equation:

y=2x^2+12x+14\\\\a=2,\ b=12,\ c=14\\\\h=\dfrac{-12}{2(2)}=\dfrac{-12}{4}=-3\\\\k=f(-3)=2(-3)^2+12(-3)+12=2(9)-36+12=18-36+12=-6

Finally:

y=2(x-(-3))^2+(-6)=2(x+3)^2-6

7 0
3 years ago
In a 3 hour examination of 350 questions, there are 50 mathematics problems. if twice as much time should be allowed for each ma
Margarita [4]

Answer: 7 minutes

Step-by-step explanation:

350/50=7

3*2.3333=7

3 0
3 years ago
Solve for x given that CE=36. Show your work.
inna [77]

Answer:

<u>The answer for this equation is x = 7</u>

Step-by-step explanation:

1. Solve for x given that CE=36

9 + 3x + 6 = 36

3x + 15 = 36

3x = 36 - 15  (Putting x on the left side and all the numeric values on the right)

3x = 21

<u>x = 7 (Dividing by 3 at both sides)</u>

2. Proof of replacing x by 7

9 + 3 (7) + 6 = 36

9 + 21 + 6 = 36

<u>36 = 36</u>

<u>It proves that x = 7 is correct</u>

8 0
3 years ago
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