Question

A runner is participating in a 10.3 mile race. If the runner stopped at a water station that is twice as far from the starting line as from the finish​ line, how far is the runner from the finish​ line?

Answer 1

We have the representation of this problem in the figure below. As we have a 10.3 mile race, then the equation is fulfilled as:

$d = 10.3mi = d_{1}+ d_{2}$

We know that there is a water station that is twice as far from the starting line as from the finish​ line, then:

$d_{2}=2d_{1}$

So:

$d_{1} +2d_{1}=10.3$
∴ $d_{1}=3.43mi$

and $d_{2}=2(3.43)=6.86mi$

Finally, the distance of the runner from the finish​ line is:

$6.86mi$

Answer 2

Answer:

6.86

Step-by-step explanation: