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pochemuha
3 years ago
8

Can someone explain how to solve this?

Mathematics
1 answer:
Irina18 [472]3 years ago
3 0

Answer:

(-8,8)

Step-by-step explanation:

Simplify |n| + 4 < 12.  To do this, subtract 4 from both sides.  This results in:

|n| < 8.  The solution set includes all real numbers between -8 and 8, but not -8 itself or 8 itself.

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Identify the property shown: 9 + 3 - 6 = 3 - 6 + 9
EastWind [94]

Answer:

Step-by-step explanation:

1. which property is shown by 6 + 9 = 9 + 6

A) Commutative property of addition

B) Distributiove property

C) Identity property of addition

D) Associative property of addition

2. Which symbol will make /-8/ ? 8 true?

A) >

B) <

C) =

D) inequality

Um would this help at all I mean I think question is similar?

6 0
3 years ago
Read 2 more answers
What is the volume of a right circular cylinder with a base diameter of 6 m and a height of 5 m?
DaniilM [7]

Answer:

141.3 cubic inches

Step-by-step explanation:

The volume of a cylinder is found using the volume formula V=\pi r^2h.

The radius is half the diameter 6 which is 3.

Substitute h=5 and r = 3.

V = \pi r^2h\\V = \pi (3^2)(5)\\V=\pi *9*5\\V = 45\pi \\V= 141.3

4 0
4 years ago
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Carly is playing her violin at a music festival and earns $8 for each song she plays. Maxwell is playing at a local coffee shop
sveta [45]

Answer:

If you wanted to know how much songs Maxwell will have to play to pay the fee to play there, ($50 dollars)  he will have to play 5 songs.

Step-by-step explanation:

The question to the awnser is how much can 10 go into 50. That means you have to divide 50 by 10. You can put 10 5 times into 50, and you can make sure of that by timing 10 by 5. I have no idea though what you need. Sorry if im saying somthing different than wht you want.

3 0
2 years ago
What is the surface area of the cube?
iren2701 [21]

Answer:

150 is the answer

Step-by-step explanation:

5 x 5 = 25

25 x 6 = 150.

3 0
3 years ago
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2,17,82,257,626,1297 next one please ?​
In-s [12.5K]

The easy thing to do is notice that 1^4 = 1, 2^4 = 16, 3^4 = 81, and so on, so the sequence follows the rule n^4+1. The next number would then be fourth power of 7 plus 1, or 2402.

And the harder way: Denote the <em>n</em>-th term in this sequence by a_n, and denote the given sequence by \{a_n\}_{n\ge1}.

Let b_n denote the <em>n</em>-th term in the sequence of forward differences of \{a_n\}, defined by

b_n=a_{n+1}-a_n

for <em>n</em> ≥ 1. That is, \{b_n\} is the sequence with

b_1=a_2-a_1=17-2=15

b_2=a_3-a_2=82-17=65

b_3=a_4-a_3=175

b_4=a_5-a_4=369

b_5=a_6-a_5=671

and so on.

Next, let c_n denote the <em>n</em>-th term of the differences of \{b_n\}, i.e. for <em>n</em> ≥ 1,

c_n=b_{n+1}-b_n

so that

c_1=b_2-b_1=65-15=50

c_2=110

c_3=194

c_4=302

etc.

Again: let d_n denote the <em>n</em>-th difference of \{c_n\}:

d_n=c_{n+1}-c_n

d_1=c_2-c_1=60

d_2=84

d_3=108

etc.

One more time: let e_n denote the <em>n</em>-th difference of \{d_n\}:

e_n=d_{n+1}-d_n

e_1=d_2-d_1=24

e_2=24

etc.

The fact that these last differences are constant is a good sign that e_n=24 for all <em>n</em> ≥ 1. Assuming this, we would see that \{d_n\} is an arithmetic sequence given recursively by

\begin{cases}d_1=60\\d_{n+1}=d_n+24&\text{for }n>1\end{cases}

and we can easily find the explicit rule:

d_2=d_1+24

d_3=d_2+24=d_1+24\cdot2

d_4=d_3+24=d_1+24\cdot3

and so on, up to

d_n=d_1+24(n-1)

d_n=24n+36

Use the same strategy to find a closed form for \{c_n\}, then for \{b_n\}, and finally \{a_n\}.

\begin{cases}c_1=50\\c_{n+1}=c_n+24n+36&\text{for }n>1\end{cases}

c_2=c_1+24\cdot1+36

c_3=c_2+24\cdot2+36=c_1+24(1+2)+36\cdot2

c_4=c_3+24\cdot3+36=c_1+24(1+2+3)+36\cdot3

and so on, up to

c_n=c_1+24(1+2+3+\cdots+(n-1))+36(n-1)

Recall the formula for the sum of consecutive integers:

1+2+3+\cdots+n=\displaystyle\sum_{k=1}^nk=\frac{n(n+1)}2

\implies c_n=c_1+\dfrac{24(n-1)n}2+36(n-1)

\implies c_n=12n^2+24n+14

\begin{cases}b_1=15\\b_{n+1}=b_n+12n^2+24n+14&\text{for }n>1\end{cases}

b_2=b_1+12\cdot1^2+24\cdot1+14

b_3=b_2+12\cdot2^2+24\cdot2+14=b_1+12(1^2+2^2)+24(1+2)+14\cdot2

b_4=b_3+12\cdot3^2+24\cdot3+14=b_1+12(1^2+2^2+3^2)+24(1+2+3)+14\cdot3

and so on, up to

b_n=b_1+12(1^2+2^2+3^2+\cdots+(n-1)^2)+24(1+2+3+\cdots+(n-1))+14(n-1)

Recall the formula for the sum of squares of consecutive integers:

1^2+2^2+3^2+\cdots+n^2=\displaystyle\sum_{k=1}^nk^2=\frac{n(n+1)(2n+1)}6

\implies b_n=15+\dfrac{12(n-1)n(2(n-1)+1)}6+\dfrac{24(n-1)n}2+14(n-1)

\implies b_n=4n^3+6n^2+4n+1

\begin{cases}a_1=2\\a_{n+1}=a_n+4n^3+6n^2+4n+1&\text{for }n>1\end{cases}

a_2=a_1+4\cdot1^3+6\cdot1^2+4\cdot1+1

a_3=a_2+4(1^3+2^3)+6(1^2+2^2)+4(1+2)+1\cdot2

a_4=a_3+4(1^3+2^3+3^3)+6(1^2+2^2+3^2)+4(1+2+3)+1\cdot3

\implies a_n=a_1+4\displaystyle\sum_{k=1}^3k^3+6\sum_{k=1}^3k^2+4\sum_{k=1}^3k+\sum_{k=1}^{n-1}1

\displaystyle\sum_{k=1}^nk^3=\frac{n^2(n+1)^2}4

\implies a_n=2+\dfrac{4(n-1)^2n^2}4+\dfrac{6(n-1)n(2n)}6+\dfrac{4(n-1)n}2+(n-1)

\implies a_n=n^4+1

4 0
3 years ago
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