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vlada-n [284]
4 years ago
11

FIND THE SURFACE AREA HELP ASAP GET BRAINLISTS

Mathematics
1 answer:
3241004551 [841]4 years ago
4 0

Answer:

\large\boxed{a.\ 7200\pi\ mm^2}

Step-by-step explanation:

The formula of a surface area of a cylinder:

S.A.=2\pi r(r+H)

r - radius

H - height

We have r = 40mm and H = 50mm. Substitute:

S.A.=2\pi(40)(40+50)=80\pi(90)=7200\pi\ mm^2

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an adult panda can eat 138 pounds of bamboo each day. how many pounds of bamboo can a panda eat in a week.?
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966 pounds a week

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4 years ago
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BabaBlast [244]
Linear- blue graph, table 2, 2x-3y=7, y=3\x +2, y=-4
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4 years ago
Solve -2/3x &gt; 8 or -2/3x &lt; 4.
dezoksy [38]

Answer:

B) {x| x<-12 or x>-6}

Step-by-step explanation:

-2/3x>8

change -2/3 as -3/2 and multiply both sides by -3/2x

-2/3x•(-2/3)x<-3/2•8

calculate

reduce

x<-3•4

multiply numbers

-----------

x<-12

-----------

now we're done with the first equation, let's do the other equation to find the answer!

-2/3x<4

multiply both sides by -3/2 and again change -2/3 by -3/2

-3/2•(-2/3)x>-3/2•4

calculate

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x>-3•2

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----------

x>-6

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6 0
4 years ago
Please help me
lisabon 2012 [21]

Answer:

5

Step-by-step explanation:

3+2x = 4x-7

3+7=4x-2x

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3 0
2 years ago
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The following random sample was selected from a normal distribution: 4.5, 6.4, 2.3, 1.8, 5.3, then the 95% confidence interval t
kap26 [50]

Answer:

the 95% confidence interval to estimate the population mean is between  1.62 and 6.50

Step-by-step explanation:

given data

distribution = 4.5, 6.4, 2.3, 1.8, 5.3

so n = 5

confidence interval = 95%

to find out

the population mean is between

solution

first we calculate the mean i.e.

mean =  \frac{1}{n}\sum_{i=1}^{n}x(i)

mean =  4.5+ 6.4+ 2.3+ 1.8+ 5.3 / 5

mean = 4.06

now we calculate the standard deviation i.e.

standard deviation =   \sqrt{\frac{1}{n-1}\sum (x(i)-mean)^2}

standard deviation =   \sqrt{\frac{1}{5-1}\sum (x(i)-mean)^2}

standard deviation =   \sqrt{\frac{1}{5-1} (4.5-5)^2+(6.4-5)^2 +(2.3-5)^2+(1.8-5)^2+(5.3-5)^2}

standard deviation =   \sqrt{\frac{1}{4} (4.5-5)^2+(6.4-5)^2 +(2.3-5)^2+(1.8-5)^2+(5.3-5)^2}

standard deviation =  2.226544

so 95 % confidence interval is i.e. mean +/- t(5) * standard deviation/ \sqrt{n}

here t(5) will be 2.45

so

95 % confidence interval=  4.06 +/- 2.45 * 2.226 / \sqrt{5}

95 % confidence interval= 1.62 and 6.50

4 0
3 years ago
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